Math Problem Statement

If x^4 ≤ f(x) ≤ x^2 for x in [-1,1] and x^2 ≤ f(x) ≤ x^4 for x < -1 and x > 1, at what points c do you automatically know lim(x→c)f(x)? What can you say about the value of the limit at these points?

Solution

The problem presents two inequalities involving the function f(x)f(x):

  1. x4f(x)x2x^4 \leq f(x) \leq x^2 for x[1,1]x \in [-1, 1]
  2. x2f(x)x4x^2 \leq f(x) \leq x^4 for x<1x < -1 and x>1x > 1

First Part: The question asks at what points cc you automatically know limxcf(x)\lim_{x \to c} f(x), and what you can say about the value of the limit at these points.

Applying the Squeeze Theorem:

The Squeeze Theorem (also called the Sandwich Theorem) is useful here. It states that if:

g(x)f(x)h(x)g(x) \leq f(x) \leq h(x) and limxcg(x)=limxch(x)=L\lim_{x \to c} g(x) = \lim_{x \to c} h(x) = L, then limxcf(x)=L\lim_{x \to c} f(x) = L.

For x[1,1]x \in [-1, 1]: We have the inequality x4f(x)x2x^4 \leq f(x) \leq x^2. Now, let’s analyze the limits of these bounding functions as xcx \to c:

  • limxcx4=c4\lim_{x \to c} x^4 = c^4
  • limxcx2=c2\lim_{x \to c} x^2 = c^2

Thus, as x0x \to 0, both x4x^4 and x2x^2 approach 0, implying that by the Squeeze Theorem, limx0f(x)=0\lim_{x \to 0} f(x) = 0.

For any c(1,1)c \in (-1, 1), the function f(x)f(x) will be squeezed between c4c^4 and c2c^2, both of which are equal at c=±1c = \pm 1, meaning limxcf(x)=c4\lim_{x \to c} f(x) = c^4.

For x<1x < -1 and x>1x > 1: The inequalities are reversed: x2f(x)x4x^2 \leq f(x) \leq x^4. Again, let’s analyze the limits for large positive and negative values of xx:

  • As xx \to \infty, both x2x^2 and x4x^4 approach infinity, implying that f(x)f(x) \to \infty as well.
  • Similarly, as xx \to -\infty, both x2x^2 and x4x^4 approach infinity.

Thus, for large positive and negative values of xx, the function diverges to infinity.

Answer:

  • For c=0c = 0, we know limx0f(x)=0\lim_{x \to 0} f(x) = 0.
  • For c[1,1]c \in [-1, 1], the limit limxcf(x)\lim_{x \to c} f(x) is c4c^4.
  • For x>1|x| > 1, as xx \to \infty or xx \to -\infty, the limit of f(x)f(x) is infinity.

Second Part:

The second question asks at which points cc, limxcf(x)\lim_{x \to c} f(x) is known. From the first part, we automatically know the limits for:

  • c=0c = 0
  • c[1,1]c \in [-1, 1] (using the Squeeze Theorem)
  • c>1|c| > 1 (diverges to infinity)

Would you like further details or have additional questions?


Relative Questions:

  1. How does the Squeeze Theorem help in determining the limits of a function?
  2. What is the significance of the bounding functions x4x^4 and x2x^2 in this problem?
  3. How does the behavior of the function change for x[1,1]x \in [-1, 1] versus x[1,1]x \notin [-1, 1]?
  4. Why does the limit diverge for large values of xx (both positive and negative)?
  5. Can the Squeeze Theorem be applied to cases where the limits of the bounding functions are infinite?

Tip: The Squeeze Theorem is particularly useful when dealing with functions bounded by simpler ones whose limits are known at a certain point.

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Math Problem Analysis

Mathematical Concepts

Limits
Squeeze Theorem

Formulas

lim(x→c) f(x)
lim(x→c) g(x) ≤ f(x) ≤ h(x)

Theorems

Squeeze Theorem

Suitable Grade Level

Grades 11-12 (Advanced Calculus or Pre-Calculus)