To solve the problem, we need to complete the table comparing the square's side length to its area. For a square, the area is calculated as:

$\text{Area} = \text{Side Length}^2$

Let's compute the areas for the given side lengths:

Calculations:

1. For side length $1$:
   $\text{Area} = 1^2 = 1$

2. For side length $2$:
   $\text{Area} = 2^2 = 4$

3. For side length $3$:
   $\text{Area} = 3^2 = 9$

4. For side length $4$:
   $\text{Area} = 4^2 = 16$

5. For side length $5$:
   $\text{Area} = 5^2 = 25$

6. For side length $6$:
   $\text{Area} = 6^2 = 36$

Completed Table:

Would you like a more detailed explanation or have any questions?

Here are 5 related questions for deeper exploration:

1. How is the area of other shapes (e.g., rectangle, triangle) calculated?
2. What happens to the area if the side length of a square doubles?
3. Can you graph the relationship between side length and area? What does it look like?
4. What is the general formula for the perimeter of a square, and how does it compare to the area formula?
5. How do we calculate the diagonal of a square given its side length?

Tip: Remember, when the side length of a square increases linearly, its area increases quadratically!