Math Problem Statement

Can you check my answers and tell me if this is correct or this

Write the exact value of the side length, in units, of a square whose area in square units is given.

Solution

It appears that the text extraction was unsuccessful. I'll examine the image visually and provide feedback on the mathematical content based on what I can interpret.


The problem asks for the exact side lengths of squares given their areas in square units:

  1. Part a: A=36A = 36

    • Your answer: s=9s = 9 (Correct, since 36=9\sqrt{36} = 9).
  2. Part b: A=9.25A = 9.25

    • Your answer: s=9.25s = 9.25. This seems incorrect; the side length should be the square root of 9.25. Let's calculate it:
      s=9.253.04s = \sqrt{9.25} \approx 3.04.
  3. Part c: (Area not clearly visible, but seems like a larger number)

    • Your answer: Unclear, but you'll need to calculate Area\sqrt{\text{Area}}.
  4. Part d: (Area not visible)

    • Your answer: Unclear.
  5. Part e: A=0.0001A = 0.0001

    • Your answer: s=0.01s = 0.01 (Correct, since 0.0001=0.01\sqrt{0.0001} = 0.01).
  6. Part f: A=0.011A = 0.011

    • Your answer: Unclear, but s=0.0110.105s = \sqrt{0.011} \approx 0.105.

Feel free to provide more clarity or ask for further assistance with specific parts!

Would you like details on any particular question or additional explanations?

Here are 5 questions to expand on this topic:

  1. How do you find the side length of a square from its area?
  2. What are the steps to approximate square roots of decimals like 9.25?
  3. Why is it important to ensure exact values versus approximations?
  4. Can square roots be negative in this context?
  5. How does the area change if the side length is doubled?

Tip: The square root of a number gives you the length of the side of a square when the number represents its area!

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Math Problem Analysis

Mathematical Concepts

Geometry
Square Root
Area of a Square

Formulas

s = √A, where A is the area and s is the side length

Theorems

Pythagorean theorem (if context includes squares)

Suitable Grade Level

Grades 6-8