Math Problem Statement

A sum of Rs.7,800 is lent out in two parts in such a way that the simple interest on one part at 10% p.a. for 5 years is equal to that on the second part at 9% p.a. for 6 years. Find the two sums.

Solution

Solution:

We are given that a sum of Rs. 7,800 is lent in two parts such that:

  1. The simple interest on one part at 10% p.a. for 5 years is equal to the simple interest on the second part at 9% p.a. for 6 years.
  2. We need to determine the two sums.

Step 1: Key Variables

Let:

  • xx = first part lent at 10% p.a. for 5 years
  • yy = second part lent at 9% p.a. for 6 years
  • Total sum = x+y=7800x + y = 7800

The condition states: Simple Interest on first part=Simple Interest on second part.\text{Simple Interest on first part} = \text{Simple Interest on second part}.


Step 2: Simple Interest Formula

The formula for simple interest is: SI=PRT100\text{SI} = \frac{P \cdot R \cdot T}{100} where PP = principal, RR = rate, TT = time.

For the first part: SI1=x105100=50x100=0.5x\text{SI}_1 = \frac{x \cdot 10 \cdot 5}{100} = \frac{50x}{100} = 0.5x

For the second part: SI2=y96100=54y100=0.54y\text{SI}_2 = \frac{y \cdot 9 \cdot 6}{100} = \frac{54y}{100} = 0.54y

Given that the two interests are equal: 0.5x=0.54y0.5x = 0.54y


Step 3: Solve for xx and yy

From 0.5x=0.54y0.5x = 0.54y, rearrange to express xx in terms of yy: x=0.54y0.5=1.08yx = \frac{0.54y}{0.5} = 1.08y

Now substitute into x+y=7800x + y = 7800: 1.08y+y=78001.08y + y = 7800 2.08y=78002.08y = 7800 y=78002.08=3750y = \frac{7800}{2.08} = 3750

Thus: x=1.08y=1.083750=4050x = 1.08y = 1.08 \cdot 3750 = 4050


Step 4: Verify the Result

The two parts are x=4050x = 4050 and y=3750y = 3750.

  • For the first part (40504050): SI1=4050105100=2025\text{SI}_1 = \frac{4050 \cdot 10 \cdot 5}{100} = 2025

  • For the second part (37503750): SI2=375096100=2025\text{SI}_2 = \frac{3750 \cdot 9 \cdot 6}{100} = 2025

The interests are equal, satisfying the condition.


Final Answer:

The two sums are Rs. 4,050 and Rs. 3,750.

Correct Option: (a).


Do you need further clarifications or a detailed breakdown of any step?

Here are some related questions to explore:

  1. What is the formula for simple interest, and how is it applied?
  2. How can you split amounts based on interest conditions?
  3. Can you solve similar problems using algebraic substitution?
  4. How does changing the interest rate or time affect simple interest?
  5. How is the proportionality method used in solving split amount problems?

Tip: Always verify your answers by plugging the values back into the original conditions. This ensures accuracy.

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Math Problem Analysis

Mathematical Concepts

Simple Interest
Linear Equations
Algebraic Substitution

Formulas

Simple Interest = (P × R × T) / 100

Theorems

Proportionality in Simple Interest

Suitable Grade Level

Grades 9-11