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The image contains the following question:

"A motor car covers a certain distance in 50 minutes, when running with uniform speed of 54 km/hr. How much time will it take to cover the same distance when its speed is decreased to 30 km/hr?"

### Solution:

We are given:
- Speed \( S_1 = 54 \, \text{km/h} \)
- Time \( T_1 = 50 \, \text{minutes} = \frac{50}{60} \, \text{hours} = \frac{5}{6} \, \text{hours} \)

From this, we can calculate the distance covered using the formula:
\[
\text{Distance} = \text{Speed} \times \text{Time} = 54 \times \frac{5}{6} = 45 \, \text{km}
\]

Now, the car's speed is decreased to \( S_2 = 30 \, \text{km/h} \). We need to find the time \( T_2 \) it will take to cover the same distance at the reduced speed.

Using the formula:
\[
T_2 = \frac{\text{Distance}}{\text{Speed}} = \frac{45}{30} = 1.5 \, \text{hours}
\]

So, the time it will take to cover the same distance at 30 km/h is **1.5 hours** or **90 minutes**.

### Would you like more details on any part of the solution?

Here are some related questions:
1. What is the relation between speed, time, and distance?
2. How do you convert minutes to hours?
3. If the speed was reduced to 20 km/h, how much time would it take?
4. What if the speed was increased to 60 km/h instead of decreased?
5. How would the answer change if the distance were unknown but the times were given?

**Tip:** Always remember that time is inversely proportional to speed if the distance is constant.

A motor car covers a certain distance in 50 minutes, when running with uniform speed of 54 km/hr. How much time will it take to cover the same distance when its speed is decreased to 30 km/hr?

This problem involves calculating how much time it takes for a car to cover a certain distance when its speed decreases from 54 km/h to 30 km/h. Using the formula for distance and time, learn how speed and time are inversely proportional. Suitable for students in Grades 6-8.

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