Math Problem Statement
Solution
To assist you with the physics question in the image, I will provide explanations and solutions for the following parts:
Part (a)
i. Drawing and labeling the forces
The forces acting on the sphere are:
- Tension (): Acts along the string and points upward toward the pivot point.
- Gravitational force (): Acts vertically downward due to the sphere's weight.
- Centripetal force (): Acts horizontally toward the center of the circular path.
These forces are not directly drawn on the string; rather, the components of resolve into two parts:
- : Balances vertically.
- : Provides the centripetal force.
When drawing:
- Use a dot to represent the sphere.
- Draw vectors , , and with appropriate relative magnitudes based on known variables.
ii. Derivation for the speed of the sphere
Using Newton's second law:
-
In the vertical direction: Solve for :
-
In the horizontal direction: Substitute from the first equation:
-
Simplify to solve for : Substituting (radius in terms of string length):
Finally:
Part (b)
To evaluate the claim about the string being horizontal:
- If the string were perfectly horizontal (), the tension would only provide centripetal force, and no vertical component of tension would exist to counteract gravity.
- This is physically impossible as gravity () must always be balanced by a vertical component of force.
Conclusion
- The student's claim is incorrect. The string cannot be perfectly horizontal due to the requirement of a vertical force component to counteract gravity.
If you'd like further clarifications or a detailed diagram to visualize the solution, let me know.
Here are five related questions to deepen your understanding:
- What would happen to the speed of the sphere if the angle increases?
- How does the tension in the string change with the length of the string?
- How would the forces change if the sphere's mass doubled?
- What role does centripetal force play in uniform circular motion?
- Why can't a perfectly horizontal string support the sphere's motion?
Tip: Always resolve forces into components when dealing with inclined or circular motion problems. This simplifies complex interactions into manageable equations.
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Math Problem Analysis
Mathematical Concepts
Circular Motion
Newton's Second Law
Force Resolution
Formulas
T * cos(θ) = mg
T * sin(θ) = mv²/r
v = √(g * l * tan(θ) * sin(θ))
Theorems
Newton's Second Law
Centripetal Force Equation
Suitable Grade Level
Grades 11-12
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