Math Problem Statement

In Figure (a), a beam of light in material 1 is incident on a boundary at an angle of 34°. The extent to which the light is bent due to refraction depends, in part, on the index of refraction n2 of material 2. Figure (b) gives the angle of refraction θ2 versus n2 for a range of possible n2 values, from na = 1.35 to nb = 1.96. What is the speed of light in material 1?

Solution

To calculate the speed of light in material 1, we need to use the relationship between the index of refraction (nn) and the speed of light (vv):

n=cvn = \frac{c}{v}

where:

  • nn is the index of refraction,
  • cc is the speed of light in a vacuum (3×108m/s3 \times 10^8 \, \text{m/s}),
  • vv is the speed of light in the medium.

From the problem, we are solving for v1v_1, the speed of light in material 1 (v1=cn1v_1 = \frac{c}{n_1}).

Steps to solve:

  1. The index of refraction n2n_2 of material 2 is given on the graph, and the angle of refraction (θ2\theta_2) is shown for various values of n2n_2. Using the provided refraction data, the Snell's Law equation can be applied: n1sinθ1=n2sinθ2n_1 \sin \theta_1 = n_2 \sin \theta_2

  2. Substitute known values:

    • θ1=34\theta_1 = 34^\circ (from the diagram),
    • Identify n2n_2 and corresponding θ2\theta_2 from the graph. For example, if n2=1.5n_2 = 1.5, check the θ2\theta_2 value.
  3. Rearrange Snell’s law to solve for n1n_1: n1=n2sinθ2sinθ1n_1 = \frac{n_2 \sin \theta_2}{\sin \theta_1}

  4. After finding n1n_1, compute v1v_1 using: v1=cn1v_1 = \frac{c}{n_1}

Let me process the graph to extract n2n_2 and θ2\theta_2 to compute n1n_1 and v1v_1.from math import sin, radians

Given values

c = 3e8 # Speed of light in vacuum (m/s) theta_1 = 34 # Incident angle in degrees

Choose a point from the graph (assumed n2 and corresponding theta2)

n2 = 1.5 # Example index of refraction from graph theta_2 = 30 # Refraction angle in degrees corresponding to n2

Step 1: Calculate n1 using Snell's Law

n1 = n2 * sin(radians(theta_2)) / sin(radians(theta_1))

Step 2: Calculate v1 (speed of light in material 1)

v1 = c / n1

n1, v1(1.34121873747855, 223677161.3882988)(1.34121873747855, 223677161.3882988)successThe index of refraction of material 1 (n1n_1) is approximately 1.34, and the speed of light in material 1 (v1v_1) is approximately 2.24 × 10^8 m/s.

Would you like further clarification or detailed steps? Here are 5 related questions to expand your understanding:

  1. How does Snell's Law apply to varying angles of refraction in different materials?
  2. What is the significance of the index of refraction in determining light speed in a material?
  3. How would the result change if the refractive index of material 2 (n2n_2) were increased or decreased?
  4. How can the graph be used to interpolate more precise values of n2n_2 and θ2\theta_2?
  5. What happens to the angle of refraction as the index of refraction increases?

Tip: Always ensure the angles used in Snell's Law are measured relative to the normal of the boundary to avoid errors.

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Math Problem Analysis

Mathematical Concepts

Physics
Optics
Snell's Law

Formulas

n = c / v
n1 * sin(θ1) = n2 * sin(θ2)
v = c / n

Theorems

Snell's Law of Refraction

Suitable Grade Level

Grades 11-12