Math Problem Statement

Suppose a,b,c,d and w,x,y,z are two sets of vectors in some vector space V over the real numbers. If a,b,c,d spans V and w,x,y,z spans V then the collection a,b,c,d,w,x,y,z spans V. If a,b,c,d spans V and w,x,y,z spans V then the collection a,b,c,d,w spans V.

Solution

Let's break down and analyze the two statements.

Statement 1:

"If a,b,c,da, b, c, d spans VV and w,x,y,zw, x, y, z spans VV, then the collection a,b,c,d,w,x,y,za, b, c, d, w, x, y, z spans VV."

Analysis:

  • If a,b,c,da, b, c, d spans VV, it means that any vector in VV can be expressed as a linear combination of a,b,c,a, b, c, and dd.
  • Similarly, if w,x,y,zw, x, y, z spans VV, it means any vector in VV can also be expressed as a linear combination of w,x,y,w, x, y, and zz.

When you combine the two sets {a,b,c,d}\{a, b, c, d\} and {w,x,y,z}\{w, x, y, z\} into one set {a,b,c,d,w,x,y,z}\{a, b, c, d, w, x, y, z\}, the combined set will still span VV as long as the vectors in the set are linearly independent or at least one of the two sets already spans the whole space.

Since both {a,b,c,d}\{a, b, c, d\} and {w,x,y,z}\{w, x, y, z\} independently span VV, their union will also span VV because it still includes enough vectors to express any vector in VV.

Conclusion:

The first statement is true.

Statement 2:

"If a,b,c,da, b, c, d spans VV and w,x,y,zw, x, y, z spans VV, then the collection a,b,c,d,wa, b, c, d, w spans VV."

Analysis:

  • The set a,b,c,da, b, c, d spans VV, so any vector in VV can be written as a linear combination of a,b,c,da, b, c, d.
  • The set w,x,y,zw, x, y, z also spans VV, meaning any vector in VV can also be written as a linear combination of w,x,y,zw, x, y, z.

However, in this case, you are only taking the first vector from the second set, namely ww, and combining it with the set {a,b,c,d}\{a, b, c, d\}.

To determine whether the collection {a,b,c,d,w}\{a, b, c, d, w\} spans VV, we need to consider the possibility that the set {w}\{w\} does not add anything new to the span of {a,b,c,d}\{a, b, c, d\}. For example, if ww can already be expressed as a linear combination of a,b,c,da, b, c, d, then adding ww doesn't increase the span of the set.

Thus, while a,b,c,da, b, c, d spans VV, the set {a,b,c,d,w}\{a, b, c, d, w\} might not span VV unless ww is linearly independent of the other vectors in {a,b,c,d}\{a, b, c, d\}.

Conclusion:

The second statement is not necessarily true. It depends on whether ww is linearly independent of a,b,c,da, b, c, d. If ww can be written as a linear combination of the other vectors, then the collection {a,b,c,d,w}\{a, b, c, d, w\} will not span VV.


To summarize:

  1. The first statement is true.
  2. The second statement is false unless ww is linearly independent of a,b,c,da, b, c, d.

Would you like a more detailed explanation or an example to clarify this further? Here's a set of related questions for deeper understanding:

  1. How do you check if a set of vectors spans a vector space?
  2. What is the concept of linear independence, and how does it relate to spanning a space?
  3. Can a single vector span a vector space? If so, under what conditions?
  4. How does the dimension of a vector space affect the number of vectors required to span it?
  5. What happens if you add a redundant vector to a spanning set?

Tip: Always check for linear dependence or independence when combining sets of vectors. If the new vector is already in the span of the previous ones, it doesn't increase the span.

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Math Problem Analysis

Mathematical Concepts

Linear Algebra
Vector Spaces
Spanning Sets
Linear Independence

Formulas

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Theorems

Spanning Set Theorem
Linear Independence Theorem

Suitable Grade Level

Grades 11-12