from sympy import symbols, Eq

Declare the variables

Z0, Rino, Xino, Zb1, Zb2, p1, alpha = symbols('Z0 Rino Xino Zb1 Zb2 p1 alpha')

Substitute given values

Z0_val = 50 # ohms Rino_val = 23.9 # ohms Xino_val = 24.98 # ohms p1_val = 1.51 alpha_val = 0.532

Express the given equation in a readable form

Zb2_expression = ( (Z0 * Rino * alpha * Zb1 + Xino * (1 + alpha2) * Zb12 - (Rino * alpha / Z0) * Zb13) / (p1 * Zb12 - Z0 * Rino * alpha) )

Substitute known values into the equation

Zb2_expression_substituted = Zb2_expression.subs({ Z0: Z0_val, Rino: Rino_val, Xino: Xino_val, p1: p1_val, alpha: alpha_val })

Zb2_expression_substituted(-0.254296Zb1**3 + 32.04993952Zb12 + 635.74Zb1)/(1.51Zb12 - 635.74)(-0.254296Zb1**3 + 32.04993952Zb12 + 635.74Zb1)/(1.51Zb12 - 635.74)successThe substituted expression for $Z_{b2}$ is:

$Z_{b2} = \frac{-0.254296 Z_{b1}^3 + 32.04993952 Z_{b1}^2 + 635.74 Z_{b1}}{1.51 Z_{b1}^2 - 635.74}$

Would you like to calculate $Z_{b2}$ for a specific value of $Z_{b1}$, or need further explanation?

Here are five related questions you might consider:

1. What is the behavior of $Z_{b2}$ as $Z_{b1} \to 0$?
2. How does the value of $\alpha$ influence $Z_{b2}$?
3. Can the denominator $1.51 Z_{b1}^2 - 635.74$ become zero? What does that signify?
4. How does changing $R_{ino}$ affect the overall equation?
5. What are practical applications of this equation in circuit design?

Tip: To simplify analysis, consider plotting the function to visualize the dependency of $Z_{b2}$ on $Z_{b1}$.