Math Problem Statement

Find the value of x in each right triangle using the Pythagorean theorem and Pythagorean triples.

Solution

In this image, you have a set of right triangle problems where you are asked to find the value of xx. Some of the triangles require solving using the Pythagorean theorem:

a2+b2=c2a^2 + b^2 = c^2

where cc is the hypotenuse (the side opposite the right angle), and aa and bb are the legs of the triangle. Let’s go through some examples based on the layout:

Example 1: Find the value of xx

  1. For Triangle 1: Given sides 9 and 12, use the Pythagorean theorem to find xx. x2=92+122=81+144=225    x=225=15x^2 = 9^2 + 12^2 = 81 + 144 = 225 \implies x = \sqrt{225} = 15 So, x=15x = 15.

  2. For Triangle 2: Given sides 9 and 15, use the Pythagorean theorem: x2=92+152=81+225=306    x=306x^2 = 9^2 + 15^2 = 81 + 225 = 306 \implies x = \sqrt{306} x17.5x \approx 17.5.

  3. For Triangle 3: Given the hypotenuse 65 and one leg 25, find xx: 652=252+x2    4225=625+x2    x2=3600    x=3600=6065^2 = 25^2 + x^2 \implies 4225 = 625 + x^2 \implies x^2 = 3600 \implies x = \sqrt{3600} = 60 So, x=60x = 60.

  4. For Triangle 4: Given sides 3 and 4, use: x2=32+42=9+16=25    x=25=5x^2 = 3^2 + 4^2 = 9 + 16 = 25 \implies x = \sqrt{25} = 5 So, x=5x = 5.

  5. For Triangle 5: Given one leg 16 and hypotenuse 33, solve: 332=162+x2    1089=256+x2    x2=833    x=83333^2 = 16^2 + x^2 \implies 1089 = 256 + x^2 \implies x^2 = 833 \implies x = \sqrt{833} x28.9x \approx 28.9.

  6. For Triangle 6: Using the legs 11 and 28: x2=112+282=121+784=905    x=905x^2 = 11^2 + 28^2 = 121 + 784 = 905 \implies x = \sqrt{905} x30.1x \approx 30.1.

Example 2: Use a Pythagorean triple

These problems involve known Pythagorean triples (e.g., 3-4-5, 5-12-13).

  1. Triangle 7: A triple of 8,15,178, 15, 17, so x=17x = 17.

  2. Triangle 8: Using the triple 24,45,5124, 45, 51, find x=51x = 51.

  3. Triangle 9: Using the triple 28,96,x28, 96, x, solve: x=282+962=784+9216=10000=100x = \sqrt{28^2 + 96^2} = \sqrt{784 + 9216} = \sqrt{10000} = 100

  4. Triangle 10: Using the triple 5,12,135, 12, 13, so x=13x = 13.

  5. Triangle 11: Another common triple 8,10,68, 10, 6, so x=6x = 6.

  6. Triangle 12: Using 12,16,2012, 16, 20, you have x=16x = 16.

Would you like more details or explanations for any of these? Here are five related questions:

  1. How can you identify Pythagorean triples?
  2. What are some common Pythagorean triples to memorize?
  3. Why is the hypotenuse always the longest side in a right triangle?
  4. Can the Pythagorean theorem be used for non-right triangles?
  5. What is the relationship between similar triangles and the Pythagorean theorem?

Tip: Memorizing common Pythagorean triples like (3, 4, 5), (5, 12, 13), and (7, 24, 25) can make solving these problems much faster.

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Math Problem Analysis

Mathematical Concepts

Geometry
Right Triangles
Pythagorean Theorem
Pythagorean Triples

Formulas

Pythagorean theorem: a^2 + b^2 = c^2

Theorems

Pythagorean Theorem

Suitable Grade Level

Grades 8-10