https://file.aiquickdraw.com/mathbot/file/1725549126277mq534hmx.jpg

The image shows two jars being weighed on scales. The first jar weighs **120 grams** and the second jar weighs **150 grams**. Below the scales, there is a question in Hindi: 

**"ध्यान से सोचो फिर जवाब दो खाली जार का वजन कितना है?"**  
This translates to **"Think carefully and then answer: What is the weight of the empty jar?"**

To solve this, let's assume:
- Let \( W_j \) be the weight of the empty jar.
- Let \( W_c \) be the weight of the content inside the jar.

From the two scenarios:
1. \( W_j + W_c = 120 \, \text{grams} \)
2. \( W_j + 2W_c = 150 \, \text{grams} \)

We can solve this system of equations to find \( W_j \), the weight of the empty jar.

### Solving:

Subtract the first equation from the second:

\[
(W_j + 2W_c) - (W_j + W_c) = 150 - 120
\]
\[
W_c = 30 \, \text{grams}
\]

Now, substitute \( W_c = 30 \) into the first equation:
\[
W_j + 30 = 120
\]
\[
W_j = 120 - 30
\]
\[
W_j = 90 \, \text{grams}
\]

Thus, the weight of the empty jar is **90 grams**.

Would you like more details or have any questions? Here are some related questions:

1. How would the solution change if the content inside the jar was different for both jars?
2. Can we solve this problem using any other algebraic method?
3. How can we model the relationship between the jar's weight and its contents mathematically?
4. What if the scales had errors in measurement, how would it affect the answer?
5. Could this type of problem be generalized to different types of containers and contents?

**Tip:** When solving equations with two unknowns, subtracting one equation from another often helps to simplify the problem.

What is the weight of the empty jar based on the two jars being weighed on the scales: one jar weighs 120 grams, and the other jar weighs 150 grams?

This problem involves solving for the weight of an empty jar by using algebraic equations. Given two jars, one weighing 120 grams and the other 150 grams, learn how to determine the weight of the jar using a step-by-step solution suitable for Grades 6-8.

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