Math Problem Statement

Context: Abhi and Gita set out at the same time respectively from points P and Q, 81 kms apart towards Q and P, respectively. Abhi walks uniformly at the rate of 4 km/h for his entire journey. Gita also starts walking at the speed of 4 km/h but she increases her speed by 0.25 km/h at the end of every hour. How many hours will Abhi to reach point Q after meeting Gita?

Answer question

Solution

Let's solve the problem step by step:

  1. Initial Setup: Abhi and Gita start from points P and Q respectively, and these points are 81 km apart. Both start at the same time towards each other.

  2. Abhi's Speed: Abhi walks at a constant speed of 4 km/h.

  3. Gita's Speed: Gita starts walking at 4 km/h, and she increases her speed by 0.25 km/h at the end of each hour.

Step 1: Find the time and position of meeting.

We will calculate when and where they meet.

  • Let tt be the time (in hours) at which they meet.

  • Abhi's distance covered by the time of meeting is 4t4t km.

  • Gita's speed changes each hour:

    • 1st hour: 4 km/h
    • 2nd hour: 4.25 km/h
    • 3rd hour: 4.5 km/h
    • And so on...
  • Gita's distance covered in time tt is the sum of the series of distances covered per hour.

Gita's distance after tt hours is given by: Distance=4+(4+0.25)+(4+2×0.25)++(4+(t1)×0.25)\text{Distance} = 4 + (4 + 0.25) + (4 + 2 \times 0.25) + \ldots + (4 + (t-1) \times 0.25)

Simplifying, this is: Distance=t4+0.25(0+1+2++(t1))\text{Distance} = t \cdot 4 + 0.25 \cdot (0 + 1 + 2 + \ldots + (t-1))

The sum of the series 0+1+2++(t1)0 + 1 + 2 + \ldots + (t-1) is (t1)t2\frac{(t-1) \cdot t}{2}. So, Gita's distance becomes: Distance=4t+0.25(t1)t2\text{Distance} = 4t + 0.25 \cdot \frac{(t-1) \cdot t}{2}

Now, since they meet when their combined distances are 81 km: 4t+(4t+0.25(t1)t2)=814t + \left(4t + 0.25 \cdot \frac{(t-1) \cdot t}{2}\right) = 81

Simplifying this equation: 8t+0.125(t1)t=818t + 0.125 \cdot (t-1) \cdot t = 81

Let's solve this equation to find tt.The possible values for the time tt when they meet are 72-72 hours and 99 hours. Since time cannot be negative, the valid solution is t=9t = 9 hours.

Step 2: Find the time for Abhi to reach point Q after meeting Gita.

Since Abhi meets Gita after 9 hours, he still needs to cover the remaining distance to point Q:

  • Abhi's total journey from P to Q is 81 km.
  • By the time they meet, Abhi has already covered 4×9=364 \times 9 = 36 km.
  • The remaining distance for Abhi is 8136=4581 - 36 = 45 km.

Abhi walks at a constant speed of 4 km/h. So, the time required for Abhi to cover the remaining 45 km is:

Time=45 km4 km/h=11.25 hours\text{Time} = \frac{45 \text{ km}}{4 \text{ km/h}} = 11.25 \text{ hours}

Therefore, after meeting Gita, Abhi will take 11.25 hours to reach point Q.


Would you like more details or have any questions?

Here are some related questions:

  1. How far has Gita walked by the time they meet?
  2. What is Gita's speed at the moment they meet?
  3. How much distance does Gita cover in the first 5 hours?
  4. How long would it take Gita to reach point P?
  5. What if Gita increased her speed by 0.5 km/h instead of 0.25 km/h each hour?

Tip: For problems involving variable speeds, breaking down the motion into intervals and summing distances covered in each interval is key to finding solutions accurately.

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Math Problem Analysis

Mathematical Concepts

Uniform motion
Variable speed
Arithmetic series

Formulas

Arithmetic series sum formula

Theorems

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Suitable Grade Level

Grades 10-12