Math Problem Statement

Find the remaining trigonometric ratios of 𝜃 based on the given information. sin 𝜃 = −

3 2 and 𝜃 is not in QIII cos 𝜃 =

Incorrect: Your answer is incorrect. tan 𝜃 =

Incorrect: Your answer is incorrect. cot 𝜃 =

Incorrect: Your answer is incorrect. sec 𝜃 =

Incorrect: Your answer is incorrect. csc 𝜃 =

Incorrect: Your answer is incorrect.

Solution

Given that sinθ=32\sin \theta = -\frac{3}{2} is mathematically impossible (since the sine of an angle always lies between -1 and 1), I believe there may be a typographical error in the problem. Let's assume that the correct value of sinθ\sin \theta is 35-\frac{3}{5}, which is a possible value within the allowed range.

Additionally, we know that θ\theta is not in Quadrant III (QIII). Since sinθ\sin \theta is negative and θ\theta is not in QIII, θ\theta must be in Quadrant IV.

1. Find cosθ\cos \theta

Using the Pythagorean identity: sin2θ+cos2θ=1\sin^2 \theta + \cos^2 \theta = 1 Substitute sinθ=35\sin \theta = -\frac{3}{5}: (35)2+cos2θ=1\left( -\frac{3}{5} \right)^2 + \cos^2 \theta = 1 925+cos2θ=1\frac{9}{25} + \cos^2 \theta = 1 cos2θ=1925=1625\cos^2 \theta = 1 - \frac{9}{25} = \frac{16}{25} cosθ=±45\cos \theta = \pm \frac{4}{5} Since θ\theta is in Quadrant IV, cosθ\cos \theta is positive: cosθ=45\cos \theta = \frac{4}{5}

2. Find tanθ\tan \theta

The tangent function is defined as: tanθ=sinθcosθ\tan \theta = \frac{\sin \theta}{\cos \theta} Substitute sinθ=35\sin \theta = -\frac{3}{5} and cosθ=45\cos \theta = \frac{4}{5}: tanθ=3545=34\tan \theta = \frac{-\frac{3}{5}}{\frac{4}{5}} = -\frac{3}{4}

3. Find cotθ\cot \theta

The cotangent function is the reciprocal of the tangent: cotθ=1tanθ=134=43\cot \theta = \frac{1}{\tan \theta} = \frac{1}{-\frac{3}{4}} = -\frac{4}{3}

4. Find secθ\sec \theta

The secant function is the reciprocal of the cosine: secθ=1cosθ=145=54\sec \theta = \frac{1}{\cos \theta} = \frac{1}{\frac{4}{5}} = \frac{5}{4}

5. Find cscθ\csc \theta

The cosecant function is the reciprocal of the sine: cscθ=1sinθ=135=53\csc \theta = \frac{1}{\sin \theta} = \frac{1}{-\frac{3}{5}} = -\frac{5}{3}

Summary of Results:

sinθ=35\sin \theta = -\frac{3}{5} cosθ=45\cos \theta = \frac{4}{5} tanθ=34\tan \theta = -\frac{3}{4} cotθ=43\cot \theta = -\frac{4}{3} secθ=54\sec \theta = \frac{5}{4} cscθ=53\csc \theta = -\frac{5}{3}

Would you like more details on any of the steps, or do you have any questions?

Here are 5 additional related questions:

  1. What are the signs of trigonometric functions in different quadrants?
  2. How do you derive the Pythagorean identities?
  3. What are the reciprocal trigonometric identities?
  4. How can you verify the identity sin2θ+cos2θ=1\sin^2 \theta + \cos^2 \theta = 1?
  5. How do trigonometric ratios change as angles move between quadrants?

Tip: When solving trigonometric problems, always check the quadrant to determine the correct signs of the trigonometric ratios.

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Math Problem Analysis

Mathematical Concepts

Trigonometry
Trigonometric Ratios
Quadrants in the Coordinate Plane
Pythagorean Identity

Formulas

sin²(θ) + cos²(θ) = 1
tan(θ) = sin(θ) / cos(θ)
cot(θ) = 1 / tan(θ)
sec(θ) = 1 / cos(θ)
csc(θ) = 1 / sin(θ)

Theorems

Pythagorean Identity
Reciprocal Trigonometric Functions

Suitable Grade Level

Grades 10-12