Math Problem Statement

Find the unknowns in triangles using the Sine and Cosine rules, determine the appropriate rule for given data, and calculate areas of quadrilaterals and triangles.

Solution

Let's solve each of these questions step by step:

Question 6

We have three triangles, and we need to find the unknowns.

Part (a)

Given:

  • One side: 8 cm8 \text{ cm}
  • Angles: 5252^\circ and 4343^\circ

This is a non-right triangle, so we'll use the Sine Rule: asinA=bsinB\frac{a}{\sin A} = \frac{b}{\sin B} We can find the third angle: 1805243=85180^\circ - 52^\circ - 43^\circ = 85^\circ.

Let’s assign:

  • a=8 cm,A=43a = 8 \text{ cm}, A = 43^\circ
  • b=x cm,B=52b = x \text{ cm}, B = 52^\circ

8sin43=xsin52\frac{8}{\sin 43^\circ} = \frac{x}{\sin 52^\circ}

Solving for xx: x=8sin52sin43x = \frac{8 \cdot \sin 52^\circ}{\sin 43^\circ}

Part (b)

Given:

  • Sides: 10 m,11 m,12 m10 \text{ m}, 11 \text{ m}, 12 \text{ m}

We use the Cosine Rule to find angle θ\theta: c2=a2+b22abcosCc^2 = a^2 + b^2 - 2ab\cos C Let:

  • a=10 m,b=11 m,c=12 ma = 10 \text{ m}, b = 11 \text{ m}, c = 12 \text{ m}

122=102+11221011cosθ12^2 = 10^2 + 11^2 - 2 \cdot 10 \cdot 11 \cdot \cos \theta

Solve for θ\theta.

Part (c)

Given:

  • Side lengths: 4 cm,9 cm4 \text{ cm}, 9 \text{ cm}
  • Angle: 3737^\circ

Using the Cosine Rule again: c2=a2+b22abcosCc^2 = a^2 + b^2 - 2ab\cos C Let:

  • a=4 cm,b=9 cm,C=37a = 4 \text{ cm}, b = 9 \text{ cm}, C = 37^\circ

Solve for the unknown side xx.

Question 7

To determine whether to use the Sine Rule or the Cosine Rule:

  • If you know two sides and the angle between them (SAS), use the Cosine Rule.
  • If you know a side and its opposite angle along with another side or angle, use the Sine Rule.

Question 8

Find the area of quadrilateral ABCDABCD. The quadrilateral can be divided into two triangles using diagonal BDBD. We use the formula: Area=12absinC\text{Area} = \frac{1}{2}ab\sin C Calculate the areas of ABD\triangle ABD and BCD\triangle BCD separately.

Question 9

For the triangle:

  • Sides: 9 cm,12 cm,17 cm9 \text{ cm}, 12 \text{ cm}, 17 \text{ cm}

Apply Heron's Formula: s=a+b+c2s = \frac{a + b + c}{2} Area=s(sa)(sb)(sc)\text{Area} = \sqrt{s(s - a)(s - b)(s - c)}


Would you like a detailed solution for a specific question or more explanations?

Related Questions:

  1. What is the Sine Rule and when is it applied?
  2. How does the Cosine Rule differ when finding angles versus side lengths?
  3. How can Heron's Formula be used for any triangle?
  4. What other methods can be used to find the area of a quadrilateral?
  5. Why is the sum of angles in a triangle always 180180^\circ?

Tip:

Always verify if a triangle is right-angled before applying the Sine or Cosine Rule; sometimes the Pythagorean theorem might be simpler.

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Math Problem Analysis

Mathematical Concepts

Trigonometry
Geometry
Triangles
Quadrilaterals

Formulas

Sine Rule: a/sin(A) = b/sin(B)
Cosine Rule: c^2 = a^2 + b^2 - 2ab cos(C)
Area of Triangle: 1/2 ab sin(C)
Heron's Formula: Area = sqrt(s(s-a)(s-b)(s-c))

Theorems

Sine Rule
Cosine Rule
Heron's Formula

Suitable Grade Level

Grades 10-12