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Let's go through the three questions step by step.

### Question 1:
*The height of a triangle is 4 cm more than twice the length of the base. The area of the triangle is 35 square centimeters. Find the height of the triangle.*

We are given:
- Area of triangle = 35 cm²
- Height \( h \) = \( 2b + 4 \) where \( b \) is the base

The area of a triangle is given by:
\[
\text{Area} = \frac{1}{2} \times \text{base} \times \text{height}
\]
Substitute the known values:
\[
35 = \frac{1}{2} \times b \times (2b + 4)
\]
Solving this equation will give us the base \( b \), and we can then find the height \( h \).

### Question 2:
*What is the side of a square whose area is equal to the area of the triangle shown in the figure? (Ans. A = 15 cm)*

For the triangle:
- Base = 25 cm
- Height = 18 cm

The area of the triangle is:
\[
\text{Area} = \frac{1}{2} \times \text{base} \times \text{height} = \frac{1}{2} \times 25 \times 18 = 225 \, \text{cm²}
\]

The area of the square is also 225 cm². Let \( s \) be the side of the square. Then:
\[
s^2 = 225
\]
Solve for \( s \).

### Question 3:
*A sail has a spread of canvas as shown in the figure. Find the surface area of one side of the sail (Ans. A = 136.49 cm²)*

The sail is a quadrilateral, split into two right triangles:
- Right triangle 1: Base = 9 cm, Height = 12 cm
- Right triangle 2: Base = 12 cm, Height = 15 cm

The area of a right triangle is given by:
\[
\text{Area} = \frac{1}{2} \times \text{base} \times \text{height}
\]

We will calculate the area of both triangles and add them to find the total surface area of the sail.

I'll now calculate the solutions for you.It seems like I can’t do more advanced data analysis right now. Please try again later. However, I can still guide you through the problem-solving steps manually if you'd like.

Would you like me to walk you through the calculations step by step? Let me know if you have any questions or want further details!

Here are 5 related questions to expand on this:
1. How would the problem change if the area of the triangle in Question 1 was doubled?
2. Can we generalize the formula for the height of a triangle given different base-to-height relationships?
3. How does the side of a square change if the area of the triangle is tripled?
4. Could the shape of the sail (Question 3) be divided differently to calculate the area?
5. How would the area of the sail change if both triangles had the same base and height?

**Tip:** For more complex equations, breaking them into smaller steps simplifies problem-solving and helps with accuracy!

1. The height of a triangle is 4-cm more than twice the length of the base. The area of the triangle is 35 square centimeters. Find the height of the triangle. 2. What is the side of a square whose area is equal to the area of the triangle shown in the figure? 3. A sail has a spread of canvas as shown in the figure. Find the surface area of one side of the sail.

This page explains how to solve area problems for a triangle, square, and sail using basic geometric and algebraic formulas. Learn how to find the height of a triangle with a given area, the side of a square with an area equal to a triangle, and the surface area of a sail. Suitable for students in Grades 8-10.

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