Math Problem Statement

The graph of the boundary equations for a system of inequalities is shown with the system to the right. Locate the solution​ region, and identify it by finding the corners. Question content area bottom left Part 1 The corners of the solution region are    enter your response here. ​(Type ordered pairs. Use a comma to separate answers as​ needed.) . . . Question content area right Part 1 0 1 2 3 0 2 4 6 8 x y 4 x plus 2 y equals 85 x plus y equals 7

A coordinate system has a horizontal x-axis labeled from negative 0 to 3 in increments of 0.25 and a vertical y-axis labeled from negative 0 to 8 in increments of 0.5. A dashed line labeled as 4 x plus 2 y equals 8 falls from left to right and passes through the points (0,4) and (2,0). Another dashed line labeled as 5 x plus y equals 7 falls from left to right and passes through the point (0,7) and (1,2). The region above both lines and in the first quadrant is shaded. left brace Start 3 By 1 Matrix 1st Row 1st Column 4 x plus 2 y greater than 8 2nd Row 1st Column 5 x plus y greater than 7 3rd Row 1st Column x greater than or equals 0 comma y greater than or equals 0 EndMatrix

The corners of the solution region are(Type ordered pairs. Use a comma to separate answers as needed.)

Solution

To find the corners of the solution region, we solve the system of inequalities by determining the points of intersection between the boundary lines. Here are the steps:

Step 1: Solve for the intersection of the two lines

The boundary equations of the inequalities are:

  1. 4x+2y=84x + 2y = 8
  2. 5x+y=75x + y = 7

Substitution or elimination method:

From equation (2): y=75xy = 7 - 5x.

Substitute y=75xy = 7 - 5x into equation (1): 4x+2(75x)=84x + 2(7 - 5x) = 8 4x+1410x=84x + 14 - 10x = 8 6x+14=8-6x + 14 = 8 6x=6-6x = -6 x=1x = 1

Now substitute x=1x = 1 into y=75xy = 7 - 5x: y=75(1)=2y = 7 - 5(1) = 2

So, the intersection point is (1,2)(1, 2).


Step 2: Find other intersection points

  • Line 4x+2y=84x + 2y = 8:

    • When x=0x = 0, 4(0)+2y=84(0) + 2y = 8y=4y = 4. Point: (0,4)(0, 4).
    • When y=0y = 0, 4x+2(0)=84x + 2(0) = 8x=2x = 2. Point: (2,0)(2, 0).
  • Line 5x+y=75x + y = 7:

    • When x=0x = 0, 5(0)+y=75(0) + y = 7y=7y = 7. Point: (0,7)(0, 7).
    • When y=0y = 0, 5x+0=75x + 0 = 7x=7/5=1.4x = 7/5 = 1.4. Point: (1.4,0)(1.4, 0).

Step 3: Identify the corners of the solution region

The shaded region is the area above both lines and in the first quadrant. This means we consider only feasible points in the first quadrant and above both boundary lines.

The corners of the solution region are:

  1. Intersection of 4x+2y=84x + 2y = 8 and 5x+y=75x + y = 7: (1,2)(1, 2).
  2. Intersection of 4x+2y=84x + 2y = 8 with the y-axis: (0,4)(0, 4).
  3. Intersection of 5x+y=75x + y = 7 with the y-axis: (0,7)(0, 7).

Thus, the corners of the solution region are: (1,2),(0,4),(0,7)(1, 2), (0, 4), (0, 7)

Let me know if you'd like a more detailed explanation or help visualizing this solution.


Relative Questions:

  1. How do you determine whether a point lies in the solution region of a system of inequalities?
  2. Why is the solution region bounded by the first quadrant in this problem?
  3. What method is best for solving systems of linear equations graphically versus algebraically?
  4. How do you test if a corner point satisfies all inequalities in a system?
  5. What are the practical applications of finding solution regions in inequalities?

Tip:

When solving graphically, always double-check boundary intersections and confirm if the shaded region satisfies the inequalities.

Ask a new question for Free

By Image

Drop file here or Click Here to upload

Math Problem Analysis

Mathematical Concepts

Systems of Inequalities
Linear Equations
Graphing

Formulas

4x + 2y = 8
5x + y = 7

Theorems

Intersection of lines
First quadrant constraints in systems of inequalities

Suitable Grade Level

Grades 9-11