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Let's solve the system of equations using substitution:

\[
-8x - 6y = -4
\]
\[
x + y = 3
\]

### Step 1: Solve for one variable
From the second equation:

\[
x = 3 - y
\]

### Step 2: Substitute into the first equation
Replace \(x\) in the first equation:

\[
-8(3 - y) - 6y = -4
\]

### Step 3: Distribute \(-8\)

\[
-24 + 8y - 6y = -4
\]

### Step 4: Simplify

\[
-24 + 2y = -4
\]

### Step 5: Solve for \(y\)

\[
2y = 20
\]

\[
y = 10
\]

### Step 6: Find \(x\)
Using \(x = 3 - y\):

\[
x = 3 - 10 = -7
\]

### Solution:
\[
(x, y) = (-7, 10)
\]

Would you like further explanation or a step-by-step breakdown?  

### Related Questions:
1. How do you check if the solution is correct?
2. Can this system be solved using the elimination method?
3. What happens if the equations represent parallel lines?
4. How do you graphically interpret the solution of this system?
5. What is the general approach for solving any system using substitution?

### Tip:
Always substitute the found values back into the original equations to verify correctness!

Solve the system of equations using substitution:
-8x - 6y = -4
x + y = 3

Learn how to solve the system of equations -8x - 6y = -4 and x + y = 3 using the substitution method. This detailed step-by-step guide explains key algebraic concepts and provides a clear solution for Grade 8 students.

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