https://file.aiquickdraw.com/mathbot/file/1726272546341ddeu30m9.jpg

The system of equations provided in the image is:

\[
\begin{aligned}
x_1 + x_2 &= 4 \\
x_1 + 2x_2 &= 8
\end{aligned}
\]

To solve for \(x_1\) and \(x_2\), we can use substitution or elimination. Let's use elimination to solve the system.

### Step-by-Step Solution:

1. Subtract the first equation from the second to eliminate \(x_1\):
   \[
   (x_1 + 2x_2) - (x_1 + x_2) = 8 - 4
   \]
   Simplifying the equation:
   \[
   x_2 = 4
   \]

2. Now substitute \(x_2 = 4\) into the first equation:
   \[
   x_1 + 4 = 4
   \]
   Solving for \(x_1\):
   \[
   x_1 = 0
   \]

Thus, the solution is:
\[
x_1 = 0, \quad x_2 = 4
\]

Would you like more details on the steps or have any questions?

Here are 5 related questions you might find interesting:
1. How can substitution be used to solve this system of equations?
2. What happens when two equations have no solution?
3. How can this system be solved graphically?
4. How can systems of equations be applied to real-world problems?
5. How does the method of solving systems of equations change when working with three or more variables?

**Tip:** Always check your solutions by substituting them back into the original equations!

x1 + x2 = 4 and x1 + 2x2 = 8. Solve for x1 and x2.

Learn how to solve the system of linear equations: x1 + x2 = 4 and x1 + 2x2 = 8. This problem demonstrates key algebraic methods, including elimination and substitution, with step-by-step solutions. Suitable for students in Grades 7-9.

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