Math Problem Statement

x +y+3z =0 y-32x+5z = 0 4x-5y+33z= 0

solution of this

Solution

We are given the following system of linear equations:

  1. x+y+3z=0x + y + 3z = 0
  2. y32x+5z=0y - 32x + 5z = 0
  3. 4x5y+33z=04x - 5y + 33z = 0

We can solve this system using methods such as substitution, elimination, or matrix methods (like Gaussian elimination). Let's proceed step-by-step using the elimination method.

Step 1: Solve the first equation for yy

From the first equation, x+y+3z=0x + y + 3z = 0, we can solve for yy:

y=x3zy = -x - 3z

Step 2: Substitute y=x3zy = -x - 3z into the second equation

The second equation is y32x+5z=0y - 32x + 5z = 0. Substituting y=x3zy = -x - 3z into this equation:

(x3z)32x+5z=0(-x - 3z) - 32x + 5z = 0

Simplifying:

x3z32x+5z=0-x - 3z - 32x + 5z = 0

33x+2z=0-33x + 2z = 0

So, we have:

33x=2z33x = 2z

x=233zx = \frac{2}{33}z

Step 3: Substitute x=233zx = \frac{2}{33}z and y=x3zy = -x - 3z into the third equation

Now, substitute x=233zx = \frac{2}{33}z and y=x3zy = -x - 3z into the third equation 4x5y+33z=04x - 5y + 33z = 0:

First, calculate yy: y=(233z)3z=233z3z=2+9933z=10133zy = -\left(\frac{2}{33}z\right) - 3z = -\frac{2}{33}z - 3z = -\frac{2 + 99}{33}z = -\frac{101}{33}z

Now, substitute into the third equation: 4(233z)5(10133z)+33z=04\left(\frac{2}{33}z\right) - 5\left(-\frac{101}{33}z\right) + 33z = 0

Simplifying each term: 833z+50533z+33z=0\frac{8}{33}z + \frac{505}{33}z + 33z = 0

Now, combine the terms: 8+50533z+33z=0\frac{8 + 505}{33}z + 33z = 0 51333z+33z=0\frac{513}{33}z + 33z = 0

Convert 33z33z to a fraction: 51333z+108933z=0\frac{513}{33}z + \frac{1089}{33}z = 0

Now, combine: 513+108933z=0\frac{513 + 1089}{33}z = 0 160233z=0\frac{1602}{33}z = 0

Thus, z=0z = 0.

Step 4: Solve for xx and yy

Since z=0z = 0, substitute z=0z = 0 into the expressions for xx and yy:

x=233z=0x = \frac{2}{33}z = 0 y=x3z=0y = -x - 3z = 0

Final Solution:

The solution to the system of equations is: x=0,y=0,z=0x = 0, \quad y = 0, \quad z = 0

Would you like further details on this method, or do you have any questions?

Here are 5 related questions to explore:

  1. How does Gaussian elimination work for solving systems of linear equations?
  2. What are the conditions for a system of linear equations to have no solution, one solution, or infinitely many solutions?
  3. Can matrix methods like Cramer's Rule be used to solve this system? If yes, how?
  4. How do linear transformations relate to systems of linear equations?
  5. What is the geometric interpretation of a system of three linear equations in three variables?

Tip: Always check the determinant of the coefficient matrix when solving a system using matrix methods—it indicates whether the system has a unique solution.

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Math Problem Analysis

Mathematical Concepts

Linear Algebra
Systems of Linear Equations
Gaussian Elimination

Formulas

Substitution method
Elimination method
Matrix representation of linear equations

Theorems

Solution of systems of linear equations
Determinants for unique solutions

Suitable Grade Level

Grades 11-12