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To solve this system of linear equations using the augmented matrix method, we need to start by setting up the augmented matrix for the system:

Given equations:
\[
3x_1 + 4x_2 = 1
\]
\[
x_1 - 2x_2 = 7
\]

### Step 1: Write the Augmented Matrix
The augmented matrix for this system is:
\[
\begin{bmatrix} 3 & 4 & | & 1 \\ 1 & -2 & | & 7 \end{bmatrix}
\]

### Step 2: Use Row Operations to Achieve Row Echelon Form
1. First, make the first element in the first row (pivot in the first column) a 1 by dividing the entire row by 3:
   \[
   R_1 = \left[\frac{3}{3} \quad \frac{4}{3} \quad | \quad \frac{1}{3}\right] = \begin{bmatrix} 1 & \frac{4}{3} & | & \frac{1}{3} \\ 1 & -2 & | & 7 \end{bmatrix}
   \]

2. Next, eliminate the 1 below this pivot in the second row by performing the operation \( R_2 = R_2 - R_1 \):
   \[
   R_2 = \begin{bmatrix} 1 & -2 & | & 7 \end{bmatrix} - \begin{bmatrix} 1 & \frac{4}{3} & | & \frac{1}{3} \end{bmatrix} = \begin{bmatrix} 0 & -\frac{10}{3} & | & \frac{20}{3} \end{bmatrix}
   \]
   So, our matrix now looks like:
   \[
   \begin{bmatrix} 1 & \frac{4}{3} & | & \frac{1}{3} \\ 0 & -\frac{10}{3} & | & \frac{20}{3} \end{bmatrix}
   \]

3. Simplify the second row by dividing by \(-\frac{10}{3}\):
   \[
   R_2 = \left[0 \quad 1 \quad | \quad -2\right]
   \]
   The matrix becomes:
   \[
   \begin{bmatrix} 1 & \frac{4}{3} & | & \frac{1}{3} \\ 0 & 1 & | & -2 \end{bmatrix}
   \]

4. Finally, use this result to eliminate the \(\frac{4}{3}\) in the first row. Perform the operation \( R_1 = R_1 - \frac{4}{3} R_2 \):
   \[
   R_1 = \begin{bmatrix} 1 & \frac{4}{3} & | & \frac{1}{3} \end{bmatrix} - \frac{4}{3} \times \begin{bmatrix} 0 & 1 & | & -2 \end{bmatrix} = \begin{bmatrix} 1 & 0 & | & 3 \end{bmatrix}
   \]
   Now, the augmented matrix is:
   \[
   \begin{bmatrix} 1 & 0 & | & 3 \\ 0 & 1 & | & -2 \end{bmatrix}
   \]

### Step 3: Write the Solution
From this final matrix, we can see that:
\[
x_1 = 3 \quad \text{and} \quad x_2 = -2
\]

### Solution
The solution to the system is:
\[
(x_1, x_2) = (3, -2)
\]

Would you like more details on any of these steps?

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Here are 5 related questions:
1. How do you interpret row operations in the context of solving a matrix?
2. What are other methods for solving systems of linear equations besides the augmented matrix method?
3. How can you verify the solution of a system of equations?
4. What is the difference between row echelon form and reduced row echelon form?
5. How does the augmented matrix method handle inconsistent systems with no solution?

**Tip:** When solving systems of equations, always check if the system is consistent (has solutions) or inconsistent (has no solutions) before applying row reduction.

Solve the system of equations using augmented matrix methods:
3x_1 + 4x_2 = 1
x_1 - 2x_2 = 7

Learn how to solve a system of equations using augmented matrix methods, including step-by-step row operations to achieve row echelon form. This example problem includes the system 3x_1 + 4x_2 = 1 and x_1 - 2x_2 = 7, ideal for high school students in Grades 10-12.

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