The equation given in the image is:

$y = \sqrt{x + 2}$

You want to find values of $x$ and $y$ where both are positive and the value must be 5 for each pair.

Let's start by solving for $x$ based on your condition that $y = 5$. To do that:

$y = 5 = \sqrt{x + 2}$

Square both sides to remove the square root:

$25 = x + 2$

Now solve for $x$:

$x = 25 - 2 = 23$

So, when $y = 5$, $x = 23$.

Thus, the values are $x = 23$ and $y = 5$.

Would you like more details or have any questions?

Here are 5 related questions:

1. How can you verify the solution by substituting the values back into the equation?
2. What happens if you change the value of $y$ to something other than 5?
3. Can you graph this equation to see how $y$ depends on $x$?
4. How would the solution change if the equation had a negative square root?
5. What is the domain of this function given that square roots must be non-negative?

Tip: Remember, the square root function always outputs a non-negative value, so $x$ must be greater than or equal to $-2$ for the function to be valid.