Math Problem Statement

The questions are:

  1. find the slope using these points (5,3) (7,2)
  2. Find the slope using the points and determine if they are parallel, perpendicular, or intersecting (6, -9) (1,-8) (11, 4) (10, -1)
  3. Using the equations, find the slope and determine if they are parallel, perpendicular, or intersecting y = 3/4x + 8 3x - 4y = 23 4)Fill out a proof Given: 4(x+3) = 20 prove: x = 2

Solution

Let's go through each question step-by-step.

Question 1

Find the slope using the points (5, 3) and (7, 2):

The formula for the slope mm between two points (x1,y1)(x_1, y_1) and (x2,y2)(x_2, y_2) is: m=y2y1x2x1m = \frac{y_2 - y_1}{x_2 - x_1}

Using (x1,y1)=(5,3)(x_1, y_1) = (5, 3) and (x2,y2)=(7,2)(x_2, y_2) = (7, 2): m=2375=12=12m = \frac{2 - 3}{7 - 5} = \frac{-1}{2} = -\frac{1}{2}

So, the slope between the points (5, 3) and (7, 2) is 12-\frac{1}{2}.


Question 2

Find the slopes and determine if the lines are parallel, perpendicular, or intersecting:

Step 1: Find the slope between (6,9)(6, -9) and (1,8)(1, -8):

m=8(9)16=15=15m = \frac{-8 - (-9)}{1 - 6} = \frac{1}{-5} = -\frac{1}{5}

So, the slope of the line passing through (6,9)(6, -9) and (1,8)(1, -8) is 15-\frac{1}{5}.

Step 2: Find the slope between (11,4)(11, 4) and (10,1)(10, -1):

m=141011=51=5m = \frac{-1 - 4}{10 - 11} = \frac{-5}{-1} = 5

So, the slope of the line passing through (11,4)(11, 4) and (10,1)(10, -1) is 55.

Step 3: Check if the lines are parallel, perpendicular, or intersecting.

Two lines are:

  • Parallel if they have the same slope.
  • Perpendicular if the product of their slopes is 1-1.

Since the slopes are 15-\frac{1}{5} and 55, and their product is: 15×5=1-\frac{1}{5} \times 5 = -1

The lines are perpendicular.


Question 3

Using the equations, find the slopes and determine if the lines are parallel, perpendicular, or intersecting:

We are given:

  1. y=34x+8y = \frac{3}{4}x + 8
  2. 3x4y=233x - 4y = 23

Step 1: Find the slope of y=34x+8y = \frac{3}{4}x + 8.

This equation is already in slope-intercept form y=mx+by = mx + b, where mm is the slope. So, the slope of the first line is: m=34m = \frac{3}{4}

Step 2: Find the slope of 3x4y=233x - 4y = 23.

Rewrite this equation in slope-intercept form by solving for yy:

4y=3x+23-4y = -3x + 23 y=34x234y = \frac{3}{4}x - \frac{23}{4}

So, the slope of the second line is also: m=34m = \frac{3}{4}

Step 3: Determine if the lines are parallel, perpendicular, or intersecting.

Since both lines have the same slope 34\frac{3}{4}, they are parallel.


Question 4

Fill out a proof given: 4(x+3)=204(x + 3) = 20, prove: x=2x = 2:

We can solve this step-by-step as follows:

  1. Given: 4(x+3)=204(x + 3) = 20
  2. Divide both sides by 4: x+3=5x + 3 = 5
  3. Subtract 3 from both sides: x=2x = 2

Thus, we have proven that x=2x = 2.


Would you like a more detailed explanation for any of these answers?


Further Questions to Explore

  1. How would you determine if two lines with unknown slopes are parallel or perpendicular?
  2. If two lines have slopes m1m_1 and m2m_2, what other relationships can be inferred if m1m2=1m_1 \cdot m_2 = 1?
  3. How do we interpret the y-intercept in a slope-intercept equation?
  4. What does it mean for lines to intersect at an angle other than 90 degrees?
  5. How can we graphically represent the solution to an equation like 4(x+3)=204(x+3) = 20?

Tip

For verifying parallelism or perpendicularity, always double-check the slope calculations, as small errors can affect the result.

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Math Problem Analysis

Mathematical Concepts

Algebra
Coordinate Geometry
Slopes of Lines
Equation Solving
Parallel and Perpendicular Lines

Formulas

Slope formula: m = (y2 - y1) / (x2 - x1)
Slope-intercept form: y = mx + b

Theorems

Properties of parallel and perpendicular lines
Basic algebraic equation solving

Suitable Grade Level

Grades 8-10