Here are the solutions to exercises 17 to 26 from the image:

17. Passes through (-1, 1) with slope -1

Using the point-slope form:
$y - y_1 = m(x - x_1)$
Substitute $(-1, 1)$ and $m = -1$:
$y - 1 = -1(x + 1)$
Simplify:
$y = -x$

18. Passes through (2, -3) with slope 1/2

Using the point-slope form:
$y - (-3) = \frac{1}{2}(x - 2)$
Simplify:
$y + 3 = \frac{1}{2}x - 1$
$y = \frac{1}{2}x - 4$

19. Passes through (3, 4) and (2, -5)

Find the slope $m$:
$m = \frac{y_2 - y_1}{x_2 - x_1} = \frac{-5 - 4}{2 - 3} = \frac{-9}{-1} = 9$
Using point-slope form with $(3, 4)$:
$y - 4 = 9(x - 3)$
Simplify:
$y = 9x - 27 + 4$
$y = 9x - 23$

20. Passes through (-8, 0) and (-1, 3)

Find the slope $m$:
$m = \frac{y_2 - y_1}{x_2 - x_1} = \frac{3 - 0}{-1 - (-8)} = \frac{3}{7}$
Using point-slope form with $(-8, 0)$:
$y - 0 = \frac{3}{7}(x + 8)$
Simplify:
$y = \frac{3}{7}x + \frac{24}{7}$

21. Has slope -5/4 and y-intercept 6

The slope-intercept form is:
$y = mx + b$
Substitute $m = -\frac{5}{4}$ and $b = 6$:
$y = -\frac{5}{4}x + 6$

22. Has slope 1/2 and intercept -3

The slope-intercept form is:
$y = mx + b$
Substitute $m = \frac{1}{2}$ and $b = -3$:
$y = \frac{1}{2}x - 3$

23. Passes through (-12, -9) and has slope 0

A slope of 0 means the line is horizontal:
$y = -9$

24. Passes through (1/3, 4) and has no slope

No slope means the line is vertical:
$x = \frac{1}{3}$

25. Has y-intercept 4 and x-intercept -1

The equation of the line is:
$\frac{x}{-1} + \frac{y}{4} = 1$
Simplify:
$-4x + y = 4$
$y = 4x + 4$

26. Has x-intercept -6 and y-intercept 2

The equation of the line is:
$\frac{x}{-6} + \frac{y}{2} = 1$
Simplify:
$\frac{y}{2} = 1 - \frac{x}{-6}$
Multiply by 6:
$-3x + 6y = 12$
$y = \frac{1}{2}x + 2$

If you need further details, clarifications, or solutions to more exercises, let me know!

5 Follow-Up Questions:

1. How do you use the point-slope formula to derive equations?
2. Can you explain how to calculate the x- and y-intercepts of a line?
3. How does the slope of a line affect its angle and direction?
4. What happens when a line has an undefined slope? How is its equation expressed?
5. Why is the general form of a line useful, and how can you convert it to slope-intercept form?

Tip: Always plot lines visually to confirm their slopes and intercepts when possible!