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To solve the simultaneous equations \( y = -2x + 5 \) and \( y = \frac{1}{2}x + 1 \) using the graph, we need to find the point where the two lines intersect. This point represents the solution to the system of equations, as it satisfies both equations.

From the graph:
- The two lines intersect at \( (x, y) \).
- Observing the intersection point on the graph, the lines appear to meet at \( x = 2 \) and \( y = 2 \).

Thus, the solution to the system of equations is:
\[
x = 2, \quad y = 2
\]

### Verification by Substitution:
1. Substitute \( x = 2 \) into the first equation:  
   \( y = -2(2) + 5 = -4 + 5 = 1 \).
   
2. Substitute \( x = 2 \) into the second equation:  
   \( y = \frac{1}{2}(2) + 1 = 1 + 1 = 2 \).

This confirms that both values match the coordinates from the graph.

Would you like further explanation on this, or have any questions?

Here are 5 relative questions to expand on this:
1. How do you solve simultaneous equations algebraically?
2. What are the advantages of solving simultaneous equations graphically versus algebraically?
3. Can you always determine solutions by looking at a graph?
4. What do parallel lines represent in simultaneous equations?
5. How would the solution change if the slopes of the lines were different?

**Tip**: When solving graphically, check for the exact point of intersection, as small misreadings of the graph can lead to errors.

Use the diagram to work out the solution to these simultaneous equations: y = -2x + 5 and y = 1/2x + 1.

Learn how to solve the simultaneous equations y = -2x + 5 and y = 1/2x + 1 using a graphical approach. This problem demonstrates how to find the point of intersection between two linear equations. Suitable for students in Grades 8-10.

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