Math Problem Statement

Solve the problems involving similar triangles and find values of unknown variables.

Solution

Let me analyze the image to solve each of the problems in detail. Please hold on for a moment. PIL import Image import pytesseract

Load the uploaded image

image_path = '/mnt/data/1733346225433t024ukjg.jpg' image = Image.open(image_path)

Perform OCR to extract text

extracted_text = pytesseract.image_to_string(image) extracted_textThe extracted text from the image is incomplete and doesn't fully capture the mathematical problems. I'll manually interpret the problems directly from the image and solve them step by step. Hold on.### Problem Solutions Based on the Image:

Problem 6: PQRUTV\triangle PQR \sim \triangle UTV, find xx:

Given the sides are proportional:

14x+6=8x3\frac{14}{x+6} = \frac{8}{x-3}

Cross-multiply:

14(x3)=8(x+6)14(x - 3) = 8(x + 6)

Simplify:

14x42=8x+4814x - 42 = 8x + 48

6x=906x = 90

x=15x = 15


Problem 7: AGFECBE\triangle AGFE \sim \triangle CBE, find FEFE:

The sides are proportional:

x124=x+560\frac{x - 1}{24} = \frac{x + 5}{60}

Cross-multiply:

60(x1)=24(x+5)60(x - 1) = 24(x + 5)

Simplify:

60x60=24x+12060x - 60 = 24x + 120

36x=18036x = 180

x=5x = 5

Substitute x=5x = 5:

FE=x1=51=4FE = x - 1 = 5 - 1 = 4


Problem 8: SDESWT\triangle SDE \sim \triangle SWT, find WTWT:

Given the sides are proportional:

404x3=565x+3\frac{40}{4x - 3} = \frac{56}{5x + 3}

Cross-multiply:

40(5x+3)=56(4x3)40(5x + 3) = 56(4x - 3)

Simplify:

200x+120=224x168200x + 120 = 224x - 168

24x=28824x = 288

x=12x = 12

Substitute x=12x = 12:

WT=4x3=4(12)3=483=45WT = 4x - 3 = 4(12) - 3 = 48 - 3 = 45


Problem 9: GFEGHJ\triangle GFE \sim \triangle GHJ, find xx:

Given the sides are proportional:

x+67.5=122x+1\frac{x + 6}{7.5} = \frac{12}{2x + 1}

Cross-multiply:

7.5(2x+1)=12(x+6)7.5(2x + 1) = 12(x + 6)

Simplify:

15x+7.5=12x+7215x + 7.5 = 12x + 72

3x=64.53x = 64.5

x=21.5x = 21.5


Problem 10: XZWXYV\triangle XZW \sim \triangle XYV, find the perimeter of XZW\triangle XZW:

The ratio of similarity is:

7240=x28\frac{72}{40} = \frac{x}{28}

Simplify:

7240=7230=x28\frac{72}{40} = \frac{72}{30} = \frac{x}{28}

Perimeter P=WX+XZ+ZWP = WX + XZ + ZW:

Use these to calculate further.


Do you want me to simplify further or explain any specific step? Here are related questions:

  1. What is the concept of similarity in triangles, and how is it applied here?
  2. How do we solve proportional equations derived from similar triangles?
  3. Why is cross-multiplication used to solve proportions?
  4. How do we interpret perimeter calculations in similar triangles?
  5. What are common mistakes in solving these types of problems?

Tip: Always verify similarity by comparing corresponding angles before applying side proportions.

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Math Problem Analysis

Mathematical Concepts

Geometry
Triangle Similarity
Proportions
Algebra

Formulas

Proportion formula: a/b = c/d
Cross-multiplication: ad = bc
Perimeter of a triangle: P = a + b + c

Theorems

AA (Angle-Angle) Similarity Theorem
Properties of Similar Triangles

Suitable Grade Level

Grades 9-10