The image presents four right triangle problems where you are asked to solve for the missing sides or angles. Here's how to approach solving these problems:

a.

Given:

• One angle = 30°
• One leg = 8.00 m

To solve this, we can use trigonometric functions:

• $\sin(30^\circ) = \frac{\text{opposite}}{\text{hypotenuse}}$
• $\cos(30^\circ) = \frac{\text{adjacent}}{\text{hypotenuse}}$

We also have the Pythagorean theorem if needed: $c^2 = a^2 + b^2$

b.

Given:

• One angle = 60°
• One leg = 9.00 m

Use trigonometric identities similarly to find the missing sides, employing:

• $\sin(60^\circ)$
• $\cos(60^\circ)$

c.

Given:

• One angle = 85°
• Adjacent leg = 3.00 m

Again, use:

• $\tan(85^\circ) = \frac{\text{opposite}}{\text{adjacent}}$
• Pythagorean theorem can also help here.

d.

Given:

• Hypotenuse = 5.00 m
• Adjacent leg = 3.00 m

Here, we can:

• Use $\cos(\theta)$ to find the angle, where $\theta = \cos^{-1} \left( \frac{3}{5} \right)$
• Find the missing opposite side using the Pythagorean theorem.

Would you like me to go through each part in more detail with step-by-step calculations for the missing values?

Here are 5 related questions to expand your understanding:

1. How do you use sine and cosine to solve for missing triangle sides?
2. What are the key properties of right triangles that help solve these problems?
3. How does the Pythagorean theorem assist in these types of problems?
4. What is the relationship between the angles and the sides in right triangles?
5. How can trigonometric identities simplify solving real-world problems with right triangles?

Tip: Always label the sides of a right triangle (opposite, adjacent, and hypotenuse) before applying trigonometric formulas to avoid confusion.