Math Problem Statement

Find the value of x for the given triangles and solve the ramp problem as provided in the uploaded image.

Solution

Let's solve each problem step by step.


Directions: Find the value of xx.

1. Triangle with sides 10, 7, and xx. (Right triangle)

Using the Pythagorean theorem: a2+b2=c2a^2 + b^2 = c^2 Here, c=10c = 10 (hypotenuse), a=7a = 7, and b=xb = x. Substituting: 72+x2=1027^2 + x^2 = 10^2 49+x2=10049 + x^2 = 100 x2=10049=51x^2 = 100 - 49 = 51 x=517.14x = \sqrt{51} \approx 7.14


2. Triangle with sides xx, 19, and 21. (Right triangle)

Here, c=21c = 21 (hypotenuse), a=19a = 19, and b=xb = x. Substituting into the Pythagorean theorem: 192+x2=21219^2 + x^2 = 21^2 361+x2=441361 + x^2 = 441 x2=441361=80x^2 = 441 - 361 = 80 x=80=165=458.94x = \sqrt{80} = \sqrt{16 \cdot 5} = 4\sqrt{5} \approx 8.94


3. Triangle with sides 27, 16, and xx. (Right triangle)

Here, c=xc = x (hypotenuse), a=27a = 27, and b=16b = 16. Substituting: 272+162=x227^2 + 16^2 = x^2 729+256=x2729 + 256 = x^2 x2=985x^2 = 985 x=98531.42x = \sqrt{985} \approx 31.42


5. Triangle with sides 18, xx, and 20. (Right triangle)

Here, c=20c = 20 (hypotenuse), a=18a = 18, and b=xb = x. Substituting: 182+x2=20218^2 + x^2 = 20^2 324+x2=400324 + x^2 = 400 x2=400324=76x^2 = 400 - 324 = 76 x=76=419=2198.7178x = \sqrt{76} = \sqrt{4 \cdot 19} = 2\sqrt{19} \approx 8.7178


6. Isosceles trapezoid with bases 31, xx, and legs 17 and 19.

The goal is to solve for xx, the upper base. By splitting the trapezoid into two right triangles and a rectangle, the height of the triangles is given as 17. Let dd be the horizontal length of each triangle's base, so: d2+172=192d^2 + 17^2 = 19^2 d2+289=361d^2 + 289 = 361 d2=72    d=72=628.485d^2 = 72 \quad \implies \quad d = \sqrt{72} = 6\sqrt{2} \approx 8.485 The total base length is 3131, so: x=312d=312(8.485)3116.9714.03x = 31 - 2d = 31 - 2(8.485) \approx 31 - 16.97 \approx 14.03


8. Ramp problem.

The ramp length is 12 feet, the height from the ground is 3.5 feet, and the horizontal distance (xx) is unknown. Using the Pythagorean theorem: x2+3.52=122x^2 + 3.5^2 = 12^2 x2+12.25=144x^2 + 12.25 = 144 x2=14412.25=131.75x^2 = 144 - 12.25 = 131.75 x=131.7511.48feet.x = \sqrt{131.75} \approx 11.48 \, \text{feet.}


Summary of Results:

  1. x7.14x \approx 7.14
  2. x8.94x \approx 8.94
  3. x31.42x \approx 31.42
  4. x8.72x \approx 8.72
  5. x14.03x \approx 14.03
  6. x11.48feetx \approx 11.48 \, \text{feet}

Would you like detailed explanations for any specific step or concept?


Related Questions:

  1. How does the Pythagorean theorem apply to real-world scenarios like ramps or ladders?
  2. Can you explain the steps for simplifying square roots, like 76\sqrt{76} or 985\sqrt{985}?
  3. Why is it important to check if the triangle is a right triangle before using the Pythagorean theorem?
  4. How do you handle problems with trapezoids or other non-triangular shapes?
  5. What are some practical ways to estimate square roots without a calculator?

Tip: Always double-check which side of the triangle is the hypotenuse before applying the Pythagorean theorem. This avoids common errors!

Ask a new question for Free

By Image

Drop file here or Click Here to upload

Math Problem Analysis

Mathematical Concepts

Geometry
Right Triangles
Trapezoids
Pythagorean Theorem

Formulas

Pythagorean theorem: a^2 + b^2 = c^2
Distance formula for horizontal lengths in trapezoids

Theorems

Pythagorean Theorem

Suitable Grade Level

Grades 7-10