Math Problem Statement

Tentukan ukuran sisi yang belum diketahui dari setiap segitiga berikut. a. Diketahui ΔABC dengan ∠A = 90°, BC = 26 cm, dan AB = 10 cm. b. Diketahui ΔABC dengan ukuran AB = 10,2 cm, AC = 15,3 cm, dan ∠B = 90°.

Solution

The image contains a math problem related to right triangles and the Pythagorean theorem. Here is a translation and breakdown of the problem:

Problem 5: Determine the unknown side lengths of each triangle.

a. Given a right triangle ABC\triangle ABC with:

  • A=90\angle A = 90^\circ
  • BC=26cmBC = 26 \, \text{cm}
  • AB=10cmAB = 10 \, \text{cm}

Find ACAC.

Solution for a:

Using the Pythagorean theorem for a right triangle: AC2=BC2AB2AC^2 = BC^2 - AB^2

AC2=262102AC^2 = 26^2 - 10^2

AC2=676100=576AC^2 = 676 - 100 = 576

AC=576=24cmAC = \sqrt{576} = 24 \, \text{cm}

b. Given a right triangle ABC\triangle ABC with:

  • B=90\angle B = 90^\circ
  • AC=15.3cmAC = 15.3 \, \text{cm}
  • AB=10.2cmAB = 10.2 \, \text{cm}

Find BCBC.

Solution for b:

Using the Pythagorean theorem: BC2=AC2+AB2BC^2 = AC^2 + AB^2

BC2=15.32+10.22BC^2 = 15.3^2 + 10.2^2

BC2=234.09+104.04=338.13BC^2 = 234.09 + 104.04 = 338.13

BC=338.1318.4cmBC = \sqrt{338.13} \approx 18.4 \, \text{cm}

Would you like to see more details, or do you have any questions about the solution?

Related Questions:

  1. How do you apply the Pythagorean theorem to non-right triangles?
  2. What are the conditions under which the Pythagorean theorem can be used?
  3. How do you calculate the perimeter of a triangle once all sides are known?
  4. What is the relationship between trigonometric ratios and the sides of a right triangle?
  5. How do you solve problems involving special right triangles (30-60-90, 45-45-90)?

Tip: Always double-check your calculations when applying the Pythagorean theorem, especially when dealing with decimals or square roots.

Ask a new question for Free

By Image

Drop file here or Click Here to upload

Math Problem Analysis

Mathematical Concepts

Pythagorean theorem
Right triangles

Formulas

AC^2 = BC^2 - AB^2
BC^2 = AC^2 + AB^2

Theorems

Pythagorean theorem

Suitable Grade Level

Grades 8-10