This image depicts a right-angled triangle, $\triangle PQR$, where:

• $\overline{PR} = 21 \, \text{cm}$ (one leg),
• $\overline{PQ} = 35 \, \text{cm}$ (the hypotenuse).

The question likely asks for the missing side $\overline{QR}$, which can be calculated using the Pythagorean Theorem:

$PQ^2 = PR^2 + QR^2$

We can solve for $QR$:

$35^2 = 21^2 + QR^2$ $1225 = 441 + QR^2$ $QR^2 = 1225 - 441 = 784$ $QR = \sqrt{784} = 28 \, \text{cm}$

Thus, the length of side $\overline{QR}$ is $28 \, \text{cm}$.

Would you like further details or have any questions about this solution?

Here are 5 related questions to expand the problem:

1. What is the area of triangle $\triangle PQR$?
2. How do we find the angles in triangle $\triangle PQR$?
3. What is the perimeter of triangle $\triangle PQR$?
4. Can you calculate the sine, cosine, and tangent of the angles $\angle P$ and $\angle R$?
5. How would the result change if one of the side lengths was different?

Tip: Remember that in right-angled triangles, the hypotenuse is always the longest side!