https://file.aiquickdraw.com/mathbot/file/1726620483320lu7swid5.jpg

The inequality provided in the image is:

\[
0.15t + 2.50 \leq 6
\]

This inequality represents the maximum time $t$ (in minutes) for which the rental cost will be at most $6. We can solve this inequality to find the possible times.

### Steps to Solve:

1. Subtract 2.50 from both sides:

\[
0.15t \leq 6 - 2.50
\]
\[
0.15t \leq 3.50
\]

2. Divide both sides by 0.15:

\[
t \leq \frac{3.50}{0.15}
\]
\[
t \leq 23.33
\]

### Solution:

The solution to the inequality is $ t \leq 23.33 $, meaning the customer can rent the canoe for at most 23.33 minutes when they have $6.

Would you like a detailed explanation of how this applies to the graph or table? Feel free to ask!

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Here are 5 related questions you might find useful:

1. How would the inequality change if the customer had $8 instead of $6?
2. Can you graph the inequality and show the range of possible times?
3. How does the fixed fee (2.50) affect the rental time calculation?
4. What happens if the rental rate changes to $0.20 per minute? How would the inequality look?
5. How does solving this inequality relate to solving linear equations?

**Tip:** When solving inequalities, remember to reverse the inequality sign if you multiply or divide by a negative number.

For Question A, part (4), Rashida said, 'The customer can use the canoe for 23.33 minutes if she has $6.' Serena said there are other possibilities—for example, 20 minutes or 15 minutes. Rashida said you can find the answer by solving the inequality 0.15t + 2.50 <= 6. This inequality represents the times for which the rental costs at most $6. Use the table, graph, and the equation 0.15t + 2.50 = 6 to find all times for which the inequality is true. Express the solution as an inequality.

Discover how to solve the inequality 0.15t + 2.50 <= 6 for calculating possible canoe rental times with a budget of $6. This algebra problem covers solving inequalities with detailed steps suitable for high school students.

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