Math Problem Statement

solving rational equation

Solve the rational equations given in the image: (1) 2/(3 - 5) = 3x, (2) (2 + 1)/(6 - 2x) = 3, and (3) (4 + 1)/4 = 5.

Solution

You've provided a photo of a rational equation to solve. Let's go through the solution step-by-step.

The equation given is: 3x15+2x16=56\frac{3x - 1}{5} + \frac{2x - 1}{6} = \frac{5}{6}

First, we need to find a common denominator for the fractions on the left side, which is 30. We can rewrite each fraction with this common denominator: 3x15=6(3x1)30\frac{3x - 1}{5} = \frac{6(3x - 1)}{30} 2x16=5(2x1)30\frac{2x - 1}{6} = \frac{5(2x - 1)}{30} 56=2530\frac{5}{6} = \frac{25}{30}

Now, rewrite the equation: 18x6+10x530=2530\frac{18x - 6 + 10x - 5}{30} = \frac{25}{30}

Combine like terms in the numerator: 28x1130=2530\frac{28x - 11}{30} = \frac{25}{30}

Since the denominators are the same, we can equate the numerators: 28x11=2528x - 11 = 25

Now, solve for xx: 28x=25+1128x = 25 + 11 28x=3628x = 36 x=3628x = \frac{36}{28} x=97x = \frac{9}{7}

Thus, x=97x = \frac{9}{7}.

Do you want to explore further details or do you have any questions about the steps? Here are some questions you might consider:

  1. How can you check if 97\frac{9}{7} is indeed a correct solution to the equation?
  2. What happens if you were to substitute different values for xx into the original equation?
  3. What would be the graphical interpretation of this equation?
  4. How would the solution change if the equation on the right was different, say 12\frac{1}{2}?
  5. Are there scenarios where a rational equation like this would have no solution or infinite solutions?

Tip: Always simplify the fractions during your calculation to make calculations easier and avoid mistakes.

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Math Problem Analysis

Mathematical Concepts

Rational Equations
Algebra
Fraction Operations

Formulas

Equating fractions
Solving linear equations

Theorems

Cross-multiplication
Properties of equality

Suitable Grade Level

Grades 9-12