Math Problem Statement

3m/m-5 - 2/m+j = 2m^2 +8m/m^2 -4m - 5

Solution

Let's start by solving the given equation:

3mm52m+j=2m2+8mm24m5\frac{3m}{m - 5} - \frac{2}{m + j} = \frac{2m^2 + 8m}{m^2 - 4m - 5}

Step 1: Simplify the right-hand side

We can factor the quadratic in the denominator of the right-hand side:

m24m5=(m5)(m+1)m^2 - 4m - 5 = (m - 5)(m + 1)

So the equation becomes:

3mm52m+j=2m2+8m(m5)(m+1)\frac{3m}{m - 5} - \frac{2}{m + j} = \frac{2m^2 + 8m}{(m - 5)(m + 1)}

Step 2: Simplify the numerator on the right-hand side

Factor the numerator 2m2+8m2m^2 + 8m:

2m2+8m=2m(m+4)2m^2 + 8m = 2m(m + 4)

Thus, the equation becomes:

3mm52m+j=2m(m+4)(m5)(m+1)\frac{3m}{m - 5} - \frac{2}{m + j} = \frac{2m(m + 4)}{(m - 5)(m + 1)}

Step 3: Find a common denominator on the left-hand side

The first term on the left has the denominator m5m - 5 and the second term has m+jm + j. We can combine the left-hand side by finding a common denominator, but it's challenging without knowing the value of jj.

At this point, we would need more information or assumptions regarding the value of jj to proceed with solving for mm.

Do you want to continue under the assumption that jj is a constant? Or perhaps make any other clarification?


Related questions:

  1. How do you handle equations with unknown parameters like jj?
  2. How would the solution change if j=1j = 1?
  3. What are some factoring techniques for complex polynomials?
  4. How can you check the domain of rational expressions with unknown variables?
  5. What happens when m=5m = 5 or m=1m = -1 in this equation?

Tip: Always look for factorization opportunities to simplify complex algebraic expressions.

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Math Problem Analysis

Mathematical Concepts

Algebra
Rational Expressions
Factoring
Quadratic Equations

Formulas

Factoring quadratic expressions: ax^2 + bx + c
Simplifying rational expressions
Common denominator for rational expressions

Theorems

Factoring Theorem for Quadratics
Properties of Rational Expressions

Suitable Grade Level

Grades 10-12