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Let's break down and solve each part of this problem step by step.

### 1. \( 72 \div \sqrt{2253.6} \)

We need to first find \( \sqrt{2253.6} \), then divide 72 by that value.

### 2. \( 23 \div \sqrt{531.3} \)

Similarly, we will find \( \sqrt{531.3} \), and divide 23 by the result.

### 3. \( 115 \div \sqrt{7049.5} \)

Again, we calculate \( \sqrt{7049.5} \), then divide 115 by the square root.

### 4. Solve the problem:  
Audrey sold 122.5 kg of scrap fabrics. Each pack weighs about 5 kg.  
To find how many packs Audrey sold, we divide \( 122.5 \div 5 \).

I’ll compute these now.Here are the results for each problem:

1. \( 72 \div \sqrt{2253.6} \approx 1.52 \)
2. \( 23 \div \sqrt{531.3} \approx 1.00 \)
3. \( 115 \div \sqrt{7049.5} \approx 1.37 \)
4. Audrey sold \( 122.5 \div 5 = 24.5 \) packs of scrap fabrics.

Would you like further details or explanations on any of these calculations?

Here are five related questions to think about:
1. What is the general formula for dividing by a square root?
2. How can you estimate square roots without a calculator?
3. What happens if the weights of each pack vary slightly?
4. Can you solve the same problem with different units (e.g., pounds instead of kilograms)?
5. How can this method be applied to other real-life problems involving division?

**Tip**: Always double-check your square root calculations when dividing by them to avoid small rounding errors.

1. 72 ÷ √2253.6
2. 23 ÷ √531.3
3. 115 ÷ √7049.5
4. Audrey sold 122.5 kg of scrap fabrics. If each pack of scrap fabrics weighs about 5 kg, how many packs did Audrey sell?

Solve division problems involving square roots and a real-world word problem on scrap fabric packs. This covers key arithmetic and algebraic concepts suitable for Grades 6-8 students. Example: 72 ÷ √2253.6 and finding how many 5 kg packs make up 122.5 kg.

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