Math Problem Statement
The diagram shows trapezium PQRS. PQ is parallel to RS and angle PSR = 90°. PQ = x cm, PS = (x + 3) cm and RS = (3x - 2) cm. (a) Given that the area of the trapezium is 49 cm?, form an equation in x and show that it simplifies to 2x* + 5x - 52 = 0. (b) Solve the equation 2x2 + 5x - 52 = 0. (c) Hence, find the length of RS.
Solution
Step-by-step Solution
The trapezium has the following dimensions:
- , making .
Part (a): Form an equation for the area of the trapezium
The area of a trapezium is given by the formula:
Where:
- and are the lengths of the parallel sides ( and ),
- is the perpendicular height (which is in this case).
Substituting the given values:
The area of the trapezium is given as . Therefore, substituting into the area formula:
Simplifying:
Multiply both sides by 2 to eliminate the fraction:
Now, expand the right-hand side:
Subtract 98 from both sides:
Now divide the entire equation by 2 to simplify:
This is the required equation.
Part (b): Solve the quadratic equation
We will use the quadratic formula:
For the equation , we have:
- ,
- ,
- .
First, calculate the discriminant:
Now, substitute into the quadratic formula:
Thus, the two possible values for are:
Since represents a length, it must be positive. Therefore, .
Part (c): Find the length of
Now that we know , we can find the length of :
Final Answers:
- (a) The equation simplifies to .
- (b) The solution to the equation is .
- (c) The length of is .
Let me know if you need any additional details or have questions!
Questions for deeper understanding:
- How would the equation change if the area of the trapezium were different?
- What are the properties of trapeziums that help in solving such problems?
- Why did we discard the negative value of in the solution?
- How would you calculate the perimeter of trapezium using the values obtained?
- What would be the next steps if the angle was different?
Tip: When using the quadratic formula, always check whether both roots are applicable based on the context of the problem (e.g., lengths must be positive).
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Math Problem Analysis
Mathematical Concepts
Algebra
Geometry
Quadratic Equations
Area of Trapezium
Formulas
Area of a trapezium A = (1/2) * (a + b) * h
Quadratic equation formula ax² + bx + c = 0
Quadratic formula x = (-b ± √(b² - 4ac)) / (2a)
Theorems
Properties of trapeziums
Quadratic formula
Suitable Grade Level
Grades 8-10