To solve the equation \( y = x^2 \) for \( x \), it depends on the value of \( y \).

1. If you're given a specific value for \( y \), you can solve for \( x \) by taking the square root of both sides:
   \[
   x = \pm \sqrt{y}
   \]
   This gives two possible solutions for \( x \), because both positive and negative square roots will satisfy the equation.

2. If \( y \) is a general variable (without a specific value), the relationship between \( x \) and \( y \) remains \( y = x^2 \), and solving for \( x \) would require taking the square root of \( y \) as explained.

Let me know if you'd like more details, or if you have a specific value of \( y \) in mind.

### Related Questions:
1. What happens if \( y \) is negative in this equation?
2. How would this change if you had the equation \( y = x^3 \)?
3. Can you solve for \( y \) if \( x \) is given as a specific number?
4. How does this equation behave graphically?
5. What are the solutions if \( y = 16 \)?

### Tip:
Always remember that square roots yield both positive and negative solutions when solving quadratic equations.

Learn how to solve the equation y = x^2 by finding x. This algebraic problem demonstrates the concept of quadratic equations and solving for x using square roots. The detailed explanation includes both positive and negative solutions, and explores cases where y is negative. Suitable for Grades 7-9 students.

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