To solve the equation $y = x^2$ for $x$, it depends on the value of $y$.

1. If you're given a specific value for $y$, you can solve for $x$ by taking the square root of both sides: $x = \pm \sqrt{y}$ This gives two possible solutions for $x$, because both positive and negative square roots will satisfy the equation.

2. If $y$ is a general variable (without a specific value), the relationship between $x$ and $y$ remains $y = x^2$, and solving for $x$ would require taking the square root of $y$ as explained.

Let me know if you'd like more details, or if you have a specific value of $y$ in mind.

Related Questions:

1. What happens if $y$ is negative in this equation?
2. How would this change if you had the equation $y = x^3$?
3. Can you solve for $y$ if $x$ is given as a specific number?
4. How does this equation behave graphically?
5. What are the solutions if $y = 16$?

Tip:

Always remember that square roots yield both positive and negative solutions when solving quadratic equations.