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The equation provided is \( x^2 - 16 = 0 \). 

To solve for the roots, follow these steps:

1. Add 16 to both sides:
   \[
   x^2 = 16
   \]
2. Take the square root of both sides:
   \[
   x = \pm 4
   \]

Thus, the roots are \( x = 4 \) and \( x = -4 \). Since one of the roots is indeed \( -4 \), the statement is **True**.

Would you like further details or have any other questions?

Here are some related questions:
1. How do you solve quadratic equations using the quadratic formula?
2. What does it mean for a number to be a "root" of an equation?
3. Can a quadratic equation have complex roots?
4. How do we factor the difference of squares like \( x^2 - 16 \)?
5. What are the possible methods to solve quadratic equations?

**Tip:** When solving equations like \( x^2 = 16 \), always consider both the positive and negative roots!

One root of the equation x^2 - 16 = 0 is -4.

Explore the solution to the quadratic equation x^2 - 16 = 0. This problem demonstrates the difference of squares and solving for both positive and negative roots. Suitable for students in Grades 7-9.

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