https://file.aiquickdraw.com/mathbot/file/17300726165663340uqvj.jpg

The problem in the image is:

\[
s^2 - 9 = 0
\]

### Step-by-Step Solution:

1. **Isolate \( s^2 \):**
   \[
   s^2 = 9
   \]

2. **Take the square root of both sides:**
   \[
   s = \pm \sqrt{9}
   \]

3. **Simplify the square root:**
   \[
   s = \pm 3
   \]

### Answer:
\[
s = 3, -3
\]

Would you like a deeper explanation or have any questions? 

Here are five related questions to explore:
1. How do you solve equations involving higher powers like \( s^3 - 9 = 0 \)?
2. What happens when there is a negative number inside the square root, such as \( s^2 + 9 = 0 \)?
3. How can you check if the solutions to \( s^2 - 9 = 0 \) are correct?
4. What are the properties of the square root function that make \( \pm \sqrt{9} \) valid solutions?
5. How would the solution change if it was \( s^2 - 9 = k \) with \( k \) being a constant?

**Tip:** Always remember that when you take the square root of a squared term, you must consider both the positive and negative solutions.

Learn how to solve the quadratic equation s^2 - 9 = 0 using the square root property. This problem involves taking the square root of both sides and identifying positive and negative solutions. Suitable for students in Grades 8-10.

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