The problem in the image is:

$s^2 - 9 = 0$

Step-by-Step Solution:

1. Isolate $s^2$: $s^2 = 9$

2. Take the square root of both sides: $s = \pm \sqrt{9}$

3. Simplify the square root: $s = \pm 3$

Answer:

$s = 3, -3$

Would you like a deeper explanation or have any questions?

Here are five related questions to explore:

1. How do you solve equations involving higher powers like $s^3 - 9 = 0$?
2. What happens when there is a negative number inside the square root, such as $s^2 + 9 = 0$?
3. How can you check if the solutions to $s^2 - 9 = 0$ are correct?
4. What are the properties of the square root function that make $\pm \sqrt{9}$ valid solutions?
5. How would the solution change if it was $s^2 - 9 = k$ with $k$ being a constant?

Tip: Always remember that when you take the square root of a squared term, you must consider both the positive and negative solutions.