Math Problem Statement

by2−3z = cy2+5z−7, for y (don't put the plus or minus (±) here as the system will reject it ) y =

Solution

We are given the quadratic equation:

by23z=cy2+5z7by^2 - 3z = cy^2 + 5z - 7

To solve for yy, we need to first rearrange the terms so that all the terms involving yy are on one side of the equation. Let’s do that step by step:

Step 1: Move all terms involving yy to one side

We start by subtracting cy2cy^2 from both sides:

by2cy2=5z7+3zby^2 - cy^2 = 5z - 7 + 3z

This simplifies to:

(by2cy2)=8z7(by^2 - cy^2) = 8z - 7

Step 2: Factor out y2y^2

Now factor out y2y^2 from the left-hand side:

y2(bc)=8z7y^2(b - c) = 8z - 7

Step 3: Solve for y2y^2

Now divide both sides by (bc)(b - c) to solve for y2y^2:

y2=8z7bcy^2 = \frac{8z - 7}{b - c}

Step 4: Solve for yy

Finally, take the square root of both sides to solve for yy:

y=8z7bcy = \sqrt{\frac{8z - 7}{b - c}}

This is the solution for yy.


Do you have any questions or would you like further details? Here are some related questions to expand your understanding:

  1. What happens if b=cb = c in this equation?
  2. How would the equation change if we added a constant term on both sides?
  3. How can you verify if this solution is valid for specific values of bb, cc, and zz?
  4. How does the solution change if there’s a different constant instead of 8z78z - 7?
  5. What is the impact of negative values for zz on the solution?

Tip: Always double-check if the denominator of a fraction could be zero; it could indicate a special case or undefined solution.

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Math Problem Analysis

Mathematical Concepts

Algebra
Quadratic Equations
Factoring
Square Roots

Formulas

by^2 - cy^2 = 8z - 7
y^2(b - c) = 8z - 7
y = sqrt((8z - 7) / (b - c))

Theorems

Factoring
Square Root Property

Suitable Grade Level

Grades 9-11