Math Problem Statement

The discrete random variable  RR  is such that  R∈{2,4,5,7}R∈{2,4,5,7}.Given that  P(R=r)=k(r+1)r+2P(R=r)=r+2k(r+1)​, then find.

(a)

The value of the constant  kk.

(b)

P(R⩽4)P(R⩽4).

Note ⁣:Note:Give your answer in simplest fraction form only.

Solution

To solve the problem, we need to find the value of the constant kk and then compute P(R4)P(R \leq 4).

(a) Finding the constant kk

Given the probability mass function: P(R=r)=k(r+1)r+2P(R = r) = \frac{k(r + 1)}{r + 2} where R{2,4,5,7}R \in \{2, 4, 5, 7\}, we know that the sum of all probabilities must equal 1: r=2,4,5,7P(R=r)=1\sum_{r=2,4,5,7} P(R = r) = 1

Let's compute the individual probabilities: P(R=2)=k(2+1)2+2=3k4P(R = 2) = \frac{k(2 + 1)}{2 + 2} = \frac{3k}{4} P(R=4)=k(4+1)4+2=5k6P(R = 4) = \frac{k(4 + 1)}{4 + 2} = \frac{5k}{6} P(R=5)=k(5+1)5+2=6k7P(R = 5) = \frac{k(5 + 1)}{5 + 2} = \frac{6k}{7} P(R=7)=k(7+1)7+2=8k9P(R = 7) = \frac{k(7 + 1)}{7 + 2} = \frac{8k}{9}

Now, sum these probabilities: 3k4+5k6+6k7+8k9=1\frac{3k}{4} + \frac{5k}{6} + \frac{6k}{7} + \frac{8k}{9} = 1

To combine these fractions, find a common denominator. The least common multiple of 4, 6, 7, and 9 is 252. Convert each fraction: 3k4=189k252\frac{3k}{4} = \frac{189k}{252} 5k6=210k252\frac{5k}{6} = \frac{210k}{252} 6k7=216k252\frac{6k}{7} = \frac{216k}{252} 8k9=224k252\frac{8k}{9} = \frac{224k}{252}

Summing these: 189k252+210k252+216k252+224k252=1\frac{189k}{252} + \frac{210k}{252} + \frac{216k}{252} + \frac{224k}{252} = 1 839k252=1\frac{839k}{252} = 1

Solving for kk: k=252839k = \frac{252}{839}

So, the value of the constant kk is: k=252839k = \frac{252}{839}

(b) Finding P(R4)P(R \leq 4)

P(R4)=P(R=2)+P(R=4)P(R \leq 4) = P(R = 2) + P(R = 4)

Using the probabilities calculated with k=252839k = \frac{252}{839}: P(R=2)=3k4=3×2528394=7563356=189839P(R = 2) = \frac{3k}{4} = \frac{3 \times \frac{252}{839}}{4} = \frac{756}{3356} = \frac{189}{839} P(R=4)=5k6=5×2528396=12605034=210839P(R = 4) = \frac{5k}{6} = \frac{5 \times \frac{252}{839}}{6} = \frac{1260}{5034} = \frac{210}{839}

Sum these probabilities: P(R4)=189839+210839P(R \leq 4) = \frac{189}{839} + \frac{210}{839} P(R4)=399839P(R \leq 4) = \frac{399}{839}

So, the value of P(R4)P(R \leq 4) is: P(R4)=399839P(R \leq 4) = \frac{399}{839}

To summarize: (a) The value of the constant kk is 252839\frac{252}{839}. (b) P(R4)=399839P(R \leq 4) = \frac{399}{839}.

Do you want details or have any questions?

Here are 5 numbered questions for you to ask:

  1. How do you compute the sum of probabilities for a discrete random variable?
  2. What steps are involved in finding a common denominator for adding fractions?
  3. How can you simplify fractions to their simplest form?
  4. Why is it important for the sum of probabilities to equal 1?
  5. How do you interpret the result of a probability calculation?

Tip: When solving probability problems, always double-check your work to ensure that the sum of the probabilities equals 1, as this is a fundamental property of probability distributions.

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Math Problem Analysis

Mathematical Concepts

Probability Theory
Discrete Random Variables
Probability Mass Function

Formulas

Probability mass function for discrete random variables

Theorems

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Suitable Grade Level

High School