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The problem you provided involves three pipes that can fill a pool, each with a constant flow rate. Here's a breakdown of the problem:

**Problem Statement (Translated):**

We have three pipes with a constant flow rate. When the first and second pipes are used simultaneously, they take the same amount of time to fill the pool as the first pipe alone would take. The second pipe alone fills the pool in 5 hours less than the first, and the third pipe fills the pool in 4 hours more than the first.

The question is: How long does it take for each individual pipe to fill the pool on its own?

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Let’s define the time each pipe takes to fill the pool as:
- \( t_1 \) for the first pipe,
- \( t_2 \) for the second pipe,
- \( t_3 \) for the third pipe.

From the problem, we know:
1. The second pipe fills the pool 5 hours faster than the first pipe:  
   \( t_2 = t_1 - 5 \).
   
2. The third pipe fills the pool 4 hours slower than the first pipe:  
   \( t_3 = t_1 + 4 \).

3. The combined time of the first and second pipes equals the time of the first pipe alone. The inverse of time represents the flow rate, so the equation for the combined work is:  
   \[
   \frac{1}{t_1} + \frac{1}{t_2} = \frac{1}{t_1}.
   \]

Substituting \( t_2 = t_1 - 5 \) into this equation:
\[
\frac{1}{t_1} + \frac{1}{t_1 - 5} = \frac{1}{t_1}.
\]

Now we can solve this equation for \( t_1 \) and then find \( t_2 \) and \( t_3 \).

Would you like me to proceed with solving these equations?

On dispose de trois tuyaux de débit constant pour remplir la piscine. Avec les deux premiers utilisés simultanément, il faut le même temps que pour remplir avec le premier seul. Le deuxième remplit la piscine 5 heures de moins que le premier et 4 heures de plus que le troisième. Quelle est la durée de remplissage pour chaque tuyau seul?

This problem involves determining the time it takes for three pipes to fill a pool individually, given their flow rates and relations. Learn how algebra and rate formulas help solve this problem, suitable for high school students.

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