Math Problem Statement

Solve the following for x. Round to the nearest tenth (1 decimal place). Answers will look like: 0.9 or 5.8

𝑙𝑛(π‘₯+3)=4

Solution

To solve the equation ln⁑(x+3)=4\ln(x + 3) = 4, follow these steps:

Step 1: Exponentiate both sides

To eliminate the natural logarithm (ln), exponentiate both sides of the equation using the base ee: eln⁑(x+3)=e4e^{\ln(x + 3)} = e^4 Since eln⁑y=ye^{\ln y} = y, we get: x+3=e4x + 3 = e^4

Step 2: Calculate e4e^4

Using the approximate value of eβ‰ˆ2.718e \approx 2.718: e4β‰ˆ2.7184β‰ˆ54.598e^4 \approx 2.718^4 \approx 54.598

Step 3: Solve for xx

Now, subtract 3 from both sides: x=54.598βˆ’3x = 54.598 - 3 xβ‰ˆ51.6x \approx 51.6

Final Answer:

xβ‰ˆ51.6x \approx 51.6

Would you like more details on this solution or have any questions?

Related Problems:

  1. Solve ln⁑(x+5)=3\ln(x + 5) = 3 for xx.
  2. Solve ln⁑(2x)=4\ln(2x) = 4 for xx.
  3. Solve ln⁑(x2+4)=5\ln(x^2 + 4) = 5 for xx.
  4. Solve ex+2=20e^{x+2} = 20 for xx.
  5. Solve ln⁑(xβˆ’7)=6\ln(x - 7) = 6 for xx.

Tip:

Remember, to remove a natural logarithm, you exponentiate both sides using the base ee.

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Math Problem Analysis

Mathematical Concepts

Logarithms
Natural Logarithms
Exponential Functions

Formulas

ln(x) = y implies e^y = x
x + 3 = e^4

Theorems

Properties of Logarithms
Exponential Functions

Suitable Grade Level

Grades 9-12