To solve this problem, we need to evaluate the function $f(x) = 2x - 4$ for the values of $x$ given in the table and blanks provided.

1. Find $f(2)$: $f(2) = 2(2) - 4 = 4 - 4 = 0$

2. Find $f(4)$: $f(4) = 2(4) - 4 = 8 - 4 = 4$

3. Find $f(6)$: $f(6) = 2(6) - 4 = 12 - 4 = 8$

Complete Table with Missing Values:

For the table and the blank entries, we now have:

• $f(2) = 0$
• $f(4) = 4$
• $f(6) = 8$

So the answers are:

• $f(2) = 0$
• $f(4) = 4$
• $f(6) = 8$

Would you like further explanations on any of these calculations or need help with another problem?

Related Questions to Explore:

1. What would be the value of $f(x)$ if $x = -4$?
2. How would the graph of $f(x) = 2x - 4$ look on a coordinate plane?
3. What is the slope of the function $f(x) = 2x - 4$, and what does it represent?
4. How does the function $f(x) = 2x - 4$ change if we alter the constant to $-2$?
5. Can you find the x-intercept of the function $f(x) = 2x - 4$?

Tip:

For linear functions like $f(x) = 2x - 4$, knowing the slope and intercepts can help quickly graph and interpret values without extensive calculations.