These problems involve determining the missing angle in triangles, which can be solved using the triangle angle sum property. The sum of the angles in any triangle is always $180^\circ$.

Let's solve each one:

1. Problem 1:

   • Given: $37^\circ$ and $64^\circ$
   • Sum of angles = $180^\circ$
   • So, $s = 180^\circ - (37^\circ + 64^\circ) = 180^\circ - 101^\circ = 79^\circ$

   Answer: $s = 79^\circ$

2. Problem 2:

   • Given: $110^\circ$ and $162^\circ$
   • The angle $a$ seems to be external to the triangle. For external angles, the external angle is equal to the sum of the two non-adjacent interior angles.
   • So, $a = 162^\circ - 110^\circ = 52^\circ$

   Answer: $a = 52^\circ$

3. Problem 5:

   • Given: $114^\circ$ and $147^\circ$ (This also seems to involve an external angle.)
   • $h = 147^\circ - 114^\circ = 33^\circ$

   Answer: $h = 33^\circ$

4. Problem 6:

   • Given: $41^\circ$ and $139^\circ$
   • Use the triangle angle sum property:
   • $k = 180^\circ - (41^\circ + 139^\circ) = 180^\circ - 180^\circ = 0^\circ$

   Answer: $k = 0^\circ$

Would you like more details or explanations on any specific part of this solution?

Here are 5 related questions to practice:

1. If two angles of a triangle are 45° and 90°, what is the third angle?
2. Can the sum of two angles of a triangle ever exceed 180°?
3. What is the value of the exterior angle of a triangle if the two opposite interior angles are 50° and 60°?
4. How do you calculate the third angle in a triangle when the other two angles are known?