https://file.aiquickdraw.com/mathbot/file/17257674385387riv6k4x.jpg

The equation in the image is:

\[
\log_x 1000 - \log_x x^2 + (10^{-3})^0 = 0
\]

Let's break it down step by step:

### Step 1: Simplify \((10^{-3})^0\)
Any non-zero number raised to the power of 0 equals 1, so:
\[
(10^{-3})^0 = 1
\]
Thus, the equation becomes:
\[
\log_x 1000 - \log_x x^2 + 1 = 0
\]

### Step 2: Apply logarithmic rules
Using the logarithmic identity \(\log_x x^n = n\), we can simplify \(\log_x x^2\):
\[
\log_x x^2 = 2
\]
Now the equation becomes:
\[
\log_x 1000 - 2 + 1 = 0
\]

### Step 3: Combine constants
Simplify the constants:
\[
\log_x 1000 - 1 = 0
\]
This simplifies further to:
\[
\log_x 1000 = 1
\]

### Step 4: Solve for \(x\)
The equation \(\log_x 1000 = 1\) means that \(x\) raised to the power of 1 equals 1000:
\[
x^1 = 1000
\]
Thus, \(x = 1000\).

### Final Answer:
The value of \(x\) is \(1000\).

Let me know if you'd like further clarification or additional details.

---

Here are 5 related questions to expand this concept:
1. What is the general rule for solving logarithmic equations?
2. How do we handle logarithmic expressions when the base of the logarithm is unknown?
3. Can logarithms have negative bases?
4. What happens when the logarithmic base is a fraction between 0 and 1?
5. How do you convert between logarithmic and exponential forms?

**Tip:** Always simplify any constants or expressions before applying logarithmic rules to avoid mistakes.

Learn how to solve the logarithmic equation log_x 1000 − log_x x^2 + (10^-3)^0 = 0 using key algebraic concepts, including properties of logarithms and exponentiation rules. Suitable for students in Grades 9-12.

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