To solve the equation $\log_5 25 = y$, we can convert it from logarithmic form to exponential form:

$5^y = 25$

We know that $25 = 5^2$, so:

$5^y = 5^2$

Since the bases are the same, we can set the exponents equal to each other:

$y = 2$

Thus, $y = 2$.

Would you like more details or have any further questions?

Here are five related questions:

1. How do you solve equations with logarithms of different bases?
2. What is the logarithmic property for multiplying numbers inside a log function?
3. How do you express $\log_5 1$ in terms of exponents?
4. What is the inverse function of a logarithmic equation?
5. How can you solve $\log_5 (5x) = 3$?

Tip: When solving logarithmic equations, converting between logarithmic and exponential forms is often a helpful approach.