To solve the equation \( \log_5 25 = y \), we can convert it from logarithmic form to exponential form:

\[
5^y = 25
\]

We know that \( 25 = 5^2 \), so:

\[
5^y = 5^2
\]

Since the bases are the same, we can set the exponents equal to each other:

\[
y = 2
\]

Thus, \( y = 2 \).

Would you like more details or have any further questions?

Here are five related questions:
1. How do you solve equations with logarithms of different bases?
2. What is the logarithmic property for multiplying numbers inside a log function?
3. How do you express \( \log_5 1 \) in terms of exponents?
4. What is the inverse function of a logarithmic equation?
5. How can you solve \( \log_5 (5x) = 3 \)?

**Tip:** When solving logarithmic equations, converting between logarithmic and exponential forms is often a helpful approach.

Learn how to solve the logarithmic equation log_5(25) = y by converting it to its exponential form. This problem explores the logarithmic-exponential relationship and simplifies the equation to find y = 2. Suitable for students in Grades 9-12.

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