Math Problem Statement

It is given that log_5 y is a linear function of log_25 x. The intercepts on the vertical axis and on the horizontal axis of the graph of the linear function are 2 and -2/3, respectively. Which of the following is a constant?

Solution

The question reads:

It is given that log5y\log_5 y is a linear function of log25x\log_{25} x. The intercepts on the vertical axis and on the horizontal axis of the graph of the linear function are 22 and 23-\frac{2}{3}, respectively. Which of the following is a constant?


Solution

We are tasked with finding which mathematical relationship results in a constant. Let's break this down:

Step 1: Represent the linear relationship

Since log5y\log_5 y is a linear function of log25x\log_{25} x, we can write: log5y=mlog25x+c\log_5 y = m \cdot \log_{25} x + c where mm is the slope, and cc is the y-intercept.

Step 2: Use the intercepts

  • The y-intercept is given as 22, which means: When log25x=0,log5y=2.\text{When } \log_{25} x = 0, \quad \log_5 y = 2. Thus, c=2c = 2.

  • The x-intercept is given as 23-\frac{2}{3}, which means: When log5y=0,log25x=23.\text{When } \log_5 y = 0, \quad \log_{25} x = -\frac{2}{3}.

Step 3: Solve for the slope mm

Substitute the x-intercept into the linear equation: 0=m(23)+2.0 = m \cdot \left(-\frac{2}{3}\right) + 2. Solve for mm: m=223=3.m = \frac{2}{\frac{2}{3}} = 3.

Thus, the equation becomes: log5y=3log25x+2.\log_5 y = 3 \cdot \log_{25} x + 2.

Step 4: Express xx and yy in terms of base 5

Using the properties of logarithms:

  • log25x=log5xlog525=log5x2\log_{25} x = \frac{\log_5 x}{\log_5 25} = \frac{\log_5 x}{2} (since 25=5225 = 5^2),
  • Substituting this into the equation: log5y=3log5x2+2.\log_5 y = 3 \cdot \frac{\log_5 x}{2} + 2. Simplify: log5y=32log5x+2.\log_5 y = \frac{3}{2} \cdot \log_5 x + 2.

Step 5: Combine logarithms

Using the power rule of logarithms (alogbc=logbcaa \log_b c = \log_b c^a): log5y=log5(x32)+2.\log_5 y = \log_5 (x^{\frac{3}{2}}) + 2. Rewriting: log5y=log5(x32)+log5(52).\log_5 y = \log_5 (x^{\frac{3}{2}}) + \log_5 (5^2). Combine logarithms: log5y=log5(25x32).\log_5 y = \log_5 (25 \cdot x^{\frac{3}{2}}).

Thus: y=25x32.y = 25 \cdot x^{\frac{3}{2}}.

Step 6: Find the constant

From y=25x32y = 25 \cdot x^{\frac{3}{2}}, the ratio yx32\frac{y}{x^{\frac{3}{2}}} is constant: yx32=25.\frac{y}{x^{\frac{3}{2}}} = 25.

Answer:

The constant is yx32\frac{y}{x^{\frac{3}{2}}}.


Let me know if you'd like further clarifications or details! Below are 5 related questions:

  1. How do you convert logarithms with different bases?
  2. What is the significance of the slope in a linear logarithmic relationship?
  3. How do intercepts help in determining the equation of a line?
  4. What properties of logarithms were used in this problem?
  5. How do you determine if a ratio is constant for a given equation?

Tip: Always use the properties of logarithms systematically when solving equations involving multiple bases.

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Math Problem Analysis

Mathematical Concepts

Logarithmic Functions
Linear Functions
Intercepts of a Graph
Properties of Logarithms

Formulas

Linear equation: y = mx + c
Change of base: log_b(a) = log_c(a) / log_c(b)
Logarithmic power rule: a * log_b(c) = log_b(c^a)
Combining logarithms: log_b(x) + log_b(y) = log_b(xy)

Theorems

Linear relationship of functions
Logarithmic base conversion

Suitable Grade Level

Grades 10-12