Math Problem Statement

log2\log_2(x) - log2\log_2(5) = 4

Solution

To solve the equation log2(x)log2(5)=4\log_2(x) - \log_2(5) = 4, we can use properties of logarithms.

First, recall the subtraction rule for logarithms: logb(A)logb(B)=logb(AB)\log_b(A) - \log_b(B) = \log_b\left(\frac{A}{B}\right).

Applying this rule, we get: log2(x5)=4\log_2\left(\frac{x}{5}\right) = 4

Next, we convert the logarithmic equation to its exponential form: x5=24\frac{x}{5} = 2^4

Since 24=162^4 = 16, the equation becomes: x5=16\frac{x}{5} = 16

To solve for xx, multiply both sides by 5: x=16×5x = 16 \times 5 x=80x = 80

Therefore, the solution is: x=80x = 80

Would you like details or have any questions about this solution? Here are some related questions to consider:

  1. What is the general rule for converting between logarithmic and exponential forms?
  2. How do you solve logarithmic equations with different bases?
  3. Can you explain other properties of logarithms used in solving equations?
  4. What are the common mistakes to avoid when working with logarithms?
  5. How do you apply logarithmic properties in real-world applications?

Tip: When solving logarithmic equations, always remember to check if the solution is within the domain of the logarithmic function (i.e., the argument must be positive).

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Math Problem Analysis

Mathematical Concepts

Logarithms
Exponential Functions

Formulas

log_b(A) - log_b(B) = log_b(A/B)
log_b(A) = C is equivalent to A = b^C

Theorems

Properties of Logarithms
Exponentiation

Suitable Grade Level

Grades 9-11