Math Problem Statement

Solve the following logarithmic equations and quadratic equation: (i) log5(2x + 4) = 2; (ii) log2(x^2 - 6x) = 3 + log2(1 - x); (iii) Solve the quadratic equation 3x^2 - 2x - 1 = 0;

Solution

Let's go through each question from the image you've provided:

  1. Determine the highest common factors of (The question seems to be incomplete in the image, but this typically involves finding the HCF of a set of numbers or algebraic terms.)

  2. Solve the following logarithmic equations:

    (i) log5(2x+4)=2\log_5(2x + 4) = 2

    Solution: Rewrite the equation in exponential form: 2x+4=522x + 4 = 5^2 2x+4=252x + 4 = 25 2x=212x = 21 x=212=10.5x = \frac{21}{2} = 10.5

    (ii) log2(x26x)=3+log2(1x)\log_2(x^2 - 6x) = 3 + \log_2(1 - x)

    Solution: First, use the logarithmic property logablogac=logabc\log_a b - \log_a c = \log_a \frac{b}{c}: log2(x26x)log2(1x)=3\log_2(x^2 - 6x) - \log_2(1 - x) = 3 log2(x26x1x)=3\log_2\left(\frac{x^2 - 6x}{1 - x}\right) = 3 Now rewrite this in exponential form: x26x1x=23\frac{x^2 - 6x}{1 - x} = 2^3 x26x1x=8\frac{x^2 - 6x}{1 - x} = 8 Multiply both sides by 1x1 - x: x26x=8(1x)x^2 - 6x = 8(1 - x) x26x=88xx^2 - 6x = 8 - 8x x2+2x8=0x^2 + 2x - 8 = 0 Solve this quadratic equation using the formula: x=2±(2)2+482x = \frac{-2 \pm \sqrt{(2)^2 + 4 \cdot 8}}{2}

  3. Solve the following quadratic equation:

    [ 3x^

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Math Problem Analysis

Mathematical Concepts

Logarithmic Equations
Quadratic Equations

Formulas

Exponential form of logarithms: log_a(b) = c implies b = a^c
Logarithmic subtraction: log_a(b) - log_a(c) = log_a(b/c)
Quadratic formula: x = (-b ± √(b^2 - 4ac)) / 2a

Theorems

Properties of logarithms
Quadratic formula

Suitable Grade Level

Grades 10-12