Math Problem Statement

log_√6 (216)

Solution

The expression you've uploaded is:

log6216\log_{\sqrt{6}} 216

To solve this, we can use the change of base formula and simplify. Let's proceed step-by-step.

  1. Rewrite the base: We know that 6=61/2\sqrt{6} = 6^{1/2}, so we can rewrite the expression as: log61/2216\log_{6^{1/2}} 216

  2. Use the Power Rule for Logarithms: The logarithmic identity logabx=logaxb\log_{a^b} x = \frac{\log_a x}{b} applies here. Thus, we can rewrite this as: log62161/2=2log6216\frac{\log_6 216}{1/2} = 2 \cdot \log_6 216

  3. Evaluate log6216\log_6 216: We need to determine the value of log6216\log_6 216. If we assume 216=6x216 = 6^x, we find xx by solving the equation. However, 216216 is not an integer power of 66, so we would likely need a calculator to approximate this logarithm in terms of base 1010 or base ee.

Would you like me to continue with an approximation, or are you interested in additional details?


  1. How do you convert between logarithmic bases in general?
  2. What is the power rule for logarithms and when is it useful?
  3. Why might approximations be necessary for non-integer powers in logarithmic calculations?
  4. How can logarithmic identities simplify complex expressions?
  5. How does understanding fractional exponents help in evaluating logarithmic expressions?

Tip: When dealing with unusual bases, rewriting in terms of simpler expressions can make calculations easier.

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Math Problem Analysis

Mathematical Concepts

Logarithms
Change of Base Formula
Power Rule for Logarithms

Formulas

Change of Base Formula: log_a b = log_c b / log_c a
Power Rule for Logarithms: log_a^(1/n) x = (1/n) * log_a x

Theorems

Logarithmic Identities

Suitable Grade Level

Grades 10-12