Let's solve the inequality step by step:

Given inequality:

$8(x - 2) + 9 < 3(x - 1) + 5x$

Step 1: Distribute the constants inside the parentheses.

$8x - 16 + 9 < 3x - 3 + 5x$

Step 2: Simplify both sides.

$8x - 7 < 8x - 3$

Step 3: Subtract $8x$ from both sides to eliminate the $x$-terms on both sides.

$-7 < -3$

Step 4: Analyze the result.

The inequality $-7 < -3$ is always true, which means the original inequality holds for all values of $x$.

Conclusion:

The solution is that $x$ can be any real number: $x \in (-\infty, \infty)$

Would you like more details, or do you have any questions?

Here are some related questions for further practice:

1. Solve $5(x + 1) > 2(x - 3) + 7$.
2. Solve $7x + 4 \leq 3(2x - 5) + 2x$.
3. Solve $9 - 4(x - 2) > 6x + 8$.
4. Solve $10x - 3 \geq 3(4x - 1) + 2$.
5. Solve $6x - (2x + 3) < 4x + 7$.

Tip: Always simplify expressions on both sides of an equation or inequality before solving.